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Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2750835

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Shaded area is; Area sector with radius 10 units and angle acos(0.7) - Area triangle with height √(51) units and base 7 units - area sector with radius 3 units and angle 81.37307344° - area sector with radius 10 units and angle 17.2538531174° + area triangle with two side length 10 units, and angle 17.2538531174° = (acos(0.7)*1))π÷360) - ½(√(51)*7) - (9π*81.37307344)/360 -(100π*17.2538531174)/360 + ½(100)sin17.2538531174 = 39.7699415092 - 24.9949994999 - 6.39102624298 - 15.0568272777 +...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2750828

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Sir Mike Ambrose is the author of the question. Area Purple exactly in decimal square cm is; Area triangle with two side length 7.04301437734 cm and 7.01866670644 cm, and angle 100° = ½(7.04301437734*7.01866670644)sin100 = 24.3407893513 cm² ≈ 24.34 cm²

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2750821

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Calculating Area Orange. It is; Area rectangle with length 10 cm and width 5 cm + Area circle with radius 2.5 cm. = (10*5)+(π*2.5²) = 50+¼(25π) = ¼(200+25π) cm² = 69.6349540849 cm²

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2749989

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Calculating Area of the inscribed half circle. Let the radius of the inscribed half circle be a. b² = 2a² b = √(2)a units. It implies; 1² = a²+b² 1 = a²+(√(2)a)² 1 = a²+2a² a² = ⅓ a = ½√(3) units. Again, a is the radius of the inscribed half circle. Therefore, area inscribed half circle is; ½(a²)π = ½(⅓√(3))π = ½*⅓*π = ⅙(π) square units. = 0.5235987756 square units.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2749926

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Let the side length of the ascribed regular pentagon be 2 units. a = ⅕*180(5-2) a = 108° a is the single interior angle of the ascribed regular pentagon. b² = 2²+1²-2*1*2cos108 b = 2.497212041 units. (2.497212041/sin108) = (1/sinc) c = 22.3861775592° d = 180-108-c d = 49.6138224408° e = 180-d e = 130.3861775592° f = d-c f = 27.2276448816° g = 180-2d g = 80.7723551184° h = 180-g-f h = 72° (2.497212041/sin72) = (j/sin27.2276448816)  j = 1.2013397144 units....

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2749812

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a = ½(12) cm. a = 6 cm. b = ⅙*180(6-2) b = 120° b is the single interior angle of the regular hexagon. c² = 6²+12²-2*6*12cos120 c = 15.8745078664 cm. c = 6√(7) cm. c = 15.8745078664 cm. c is the radius of the sector. (15.8745078664/sin120) = (6/sind) d = 19.1066053509° e = 90+d e = 109.1066053509° e is the angle of the sector. Therefore, shaded area exactly in decimal is; Area sector with radius 6√(7) cm and angle 109.1066053509 - Area triangle with height 12 cm an...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2749450

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a²+8² = 10² a = 6 units. a is AC,the height of triangle ABC. Calculating b, radius of the inscribed circle. 10b+8b+6b = 8*6 24b = 48 b = 2 units. c = 6-b c = 4 units. d = 8-b d = 6 units. e = 10-d e = 4 units. tanf = 8/6 f = atan(4/3)° Therefore, area red is; Area triangle with height 6 units and base 8 units - Area triangle with height 4 units and base 4sin(atan(4/3)) units. ½(6*8)-½(4*4sin(atan(4/3))) = 24-8(4/5) = ⅕(120-32) = ⅕(88) square units. = 17....

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2749359

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Sir Mike Ambrose is the author of the question. The equation of the curve is; y = (8/(x-3)) + 2 Area blue is; Area trapezoid with two parallel side 5 units and 6 units, and height 2 units - Area triangle with height 6 units and base 2 units + Area under the curve at coordinates (5, 0) and (8, 0) - Area triangle with height 6 units and base 3 units. = ½(6+5)*2 - ½(6*2) + (8(In5 - In2)+6) - ½(6*3) = 11 - 6 + 8(In5-In2) + 6 - 9 = 2+8(In5-In2) square units. = 9.33032585499 square un...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2749343

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Blue area is; 2(area circle with radius 2 cm) + Area square with single side length 4 cm. = 2(4π) + 16 = 8π + 16 = 8(π+2) cm²

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2749337

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Notice; The single side length of the ascribed regular hexagon, the inscribed regular pentagon, the inscribed square, and the inscribed equilateral triangle are equal. It is 39 units. Therefore; Area green is; Area regular hexagon with single side length 39 units - Area regular pentagon with single side length 39 units + Area square with single side length 39 units - Area equilateral triangle with single side length 39 units. = (9126/4tan(180/6)) - (7605/4tan(180/5)) + (39*3...
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