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Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/1866128

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a² = 6²+12² a = 6√(5) cm. Where a is CE = EF. b² = 2(a²) b² = 2(6√(5))² b² = 360 b = 6√(10) cm. Where b is CF. Angle DCE = atan(½)° Angle ECF = 45° Angle FCM = 90-45-atan(½) Angle FCM = 18.43494882292°  tan18.43494882292 = c/12 c = 4 cm. Angle AEF = 90-atan2 Angle AEF = atan(½)° (AF)² = 36+180-2*6*6√(5)cos(atan(½)) AF = 6√(2) cm. (6/sind) = (6√(2)/sin(atan(0.5))) d = 18.43494882292° Where d is angle AFE. Angle CFM = 180-45-18.43494882292 Angle CGM = 116.56505117708° Angle CMF = 180-1...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/1865815

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Let CE = 1 unit. (1/sin20) = (a/sin40) a = 1.87938524157 units. Where a is AE. Notice; b = a-1 b = 1.87938524157-1 b = 0.87938524157 units. Where b is AD. Angle AEC = 180-20+40 Angle AEC = 120° (c/sin120) = (1/sin20) c = 2.53208888624 units. Where c is AC = BC. BE = 2.53208888624-1 BE = 1.53208888624 units. Angle BED = 180-120 = 60° (BD)² = 1.53208888624²+1-2*2.53208888624cos60 BD = 1.34729635534 units. Calculating Angle BDE (alpha, the required angle)....

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/1865498

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a = ½(180-150) a = 15° b = 60-15 b = 45° c² = 2(6²) c = 6√(2) cm. d² = 72+12²-144√(2)cos135 d= 6√(10) cm. (6√(10)/sin135) = (12/sine) e = 26.56505117708° f = 180-135-26.56505117708  f = 18.43494882292° g = 90-18.43494882292 g = 71.56505117708° tan71.56505117708 = 12/h h = 4 cm. tan71.56505117708 = j/2 j = 6 cm. It implies the height and base of the shaded region is 6 cm and 4 cm respectively. Therefore Area Shaded Region (triangle) is; ½*4*6 = ½(24) = 12 cm²

We are smart and clever!

https://onlineedumath.com/update/we-are-smart-and-clever/1865320

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Screenshot of today's teaching and learning activities with some of our very talented, smart and clever learners; Destiny (year 10), Oghenevwarhe (year 8) and Ogheneruona (year 10). Educators: Mr. Ogheneovo, Mr. Mudiaga We are smart and clever.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/1864230

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(6/sin(180-45-atan(2))) = (a/sin45) a = 4.472135955 cm. b = √(12²+6²)+a b = 17.88854382 cm. c² = 4.472135955²+6²-12*4.472135955cos(180-atan2) c = 8.94427191 cm. Where c is CF. (8.94427191/sin(180-atan2)) = (6/Sind) d = 36.86989764584° d is angle CFD. Angle BCF is; 180-(180-atan2)-36.86989764584° = atan2-36.86989764584° = 26.56505117708° Angle ECF is; 90-26.56505117708  = 63.43494882292° Notice; atan(½)+63.43494882292 = 90° It implies; sin(atan(½)) = e/12 e = 5.366563146 cm. cos(ata...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/1864150

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Area Blue Triangle is; ½*10*10sin(90-2tan(½)) = 50sin(90-2tan(½)) = 50(⅗) = 30 cm²

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/1863346

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tan60 = a/5 a = 5√(3) cm. Where a is AD. b = ½(a) b = ½(5√(3)) cm  c = atan((½(5√(3))/5) c = atan(½√(3)) Where c is angle AGB d = atan(5√(3)/5) d = atan(√(3)) Where d is angle CAG. e = 180-c-d e = 180-atan(½√(3))-atan(√(3)) e = 79.10660535087° Where e is angle AFG. Therefore; (5/sin79.10660535087) = (f/sin(atan(√(3)))) f = 4.40958551844 cm. Where f is FG. It implies; Shaded Area is; Area triangle with height 4.40958551844 cm and base 5sin(atan(0.5√(3))) cm. = 0.5*4.40958551844*5sin(...

We are smart and clever!

https://onlineedumath.com/update/we-are-smart-and-clever/1863331

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Screenshot of today's teaching and learning activities with some of our super, smart and clever learners; Ogheneruona (year 10), Manasseh (year 8) and Oghenemano (year 8). Educators; Mr. Ovo, Mr. Daniel We are smart and clever.

We are smart and clever!

https://onlineedumath.com/update/we-are-smart-and-clever/1862024

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Our certified, experienced, resilient, productive and committed Math Educators will be glad to be at your service. We make teaching and learning Mathematics fun for learners, we expose the simplicity and beauty of Mathematics to our learners, and mentor them to appreciate and love Mathematics. Communicate us to mentor/educate you Mathematics better online. We are smart and clever.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/1861855

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tanx = 4/(40-4) tanx = (1/9) x = atan(1/9) y = 2x y = 2atan(1/9) Therefore; tan(2atan(1/9)) = h/40 (9/40) = (h/40) h = 9 units.
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