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Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2116290

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Sir Mike Ambrose is the author of the question. Let R be radius of the inscribed circle. Calculating r. √(100-25) = r+√(25+r²) r = ⅓(5√(3)) cm. Therefore; Area Shaded as a single fraction in terms of π is; Area sector with radius 10cm and angle 30° - Area triangle with height 7.40536184888 cm and base ⅓(10√(3)sin30) cm. = (30*π*100÷360) - (0.5*7.40536184888*⅓(10√(3)sin30)) = ⅓(25π) - (889749425√(3)/144179222) = ( 3604480550π- 2669248275√(3))/ 432537666 cm²  = 15.4912196...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2114980

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Sir Mike Ambrose is the author of the question. Let the side length of the regular hexagon be 1 unit. Area Hexagon is; (½(6))(1/(2tan(180/6))) = 3/2tan(30) = ½(3√(3)) square units. Notice; 1/sin105 = x/sin45 x = √(3)-1 unit. y = 1.23931367493 units. z = 1.50597117915 units. a = 120-asin(0.81811048221) a = 65.10390936101° c = 54.89609063899° d = 1.10874112934 units. Area Red is; Area triangle with height 1.10874112934 units and base sin60 units. = ½*1.10874112934sin60 = (26725571√(...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2113303

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Sir Mike Ambrose is the author of the question. Let the bigger regular pentagon side length be 1 unit. a = √(2-2cos180) a = 1.61803398875 units. b = sin36/sin108 b = 0.61803398875 units. c = √(2*0.61803398875²-2*0.61803398875²cos108) c = 1 unit. It implies; Area Blue is; Area triangle with height 1.61803398875 units and base sin72 units - Area triangle with height 1.61803398875 units and base 0.61803398875sin36. = ½*1.61803398875*sin72 - ½*1.61803398875*0.61803398875sin36 = 0.7694208842...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2109559

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Sir Mike Ambrose is the author of the question. Area Blue exactly in cm² decimal form is; Area trapezoid with two parallel side (7√(2)+14) cm and 15.3137084989 cm, and height 18.4852813742 cm. = ½((7√(2)+14)+15.3137084989)*18.4852813742 = 362.433549545 cm²

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2108236

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Sir Mike Ambrose is the author of the question. Area Green is; Area triangle with height √(8(31-14√(3))) units and base √(178-72√(3))sin57.72115346403 units. = 0.5*√(8(31-14√(3)))*√(178-72√(3))sin57.72115346403 = 22.67949192422 square units. Area Red is; Area triangle with height 5√(2) units and base 6√(2) units + Area triangle with height ⅕(11√(29)) units and base ⅕(27sin(atan(5/2))) units. = ½*5√(2)*6√(2) + ½*⅕(11√(29))*⅕(27sin(atan(5/2))) = 30 + (297/10) = 597/10 square units. Therefor...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2108235

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Sir Mike Ambrose is the author of the question. Let the radius of the semicircle be 1 unit. Area Semicircle is; ½*1²*π 0.5π square units. Calculating AC = AB = BC sin67.5 = (AC)/1 AC = sin67.5 units. 1=a²+1-2acos82.5 a = 0.26105238444 units. b = AC - a b = 0.66282714807 unit. c = √(0.26105238444²(sin67.5)²-2*0.26105238444sin67.5*cos60) c= 0.82493683584 units. d = asin(0.26105238444sin60/0.82493683584) d = 15.90570135267° e = 60-d e = 44.09429864733° f = 0.650107 unit. g = 0.576911...

We are smart and clever!

https://onlineedumath.com/update/we-are-smart-and-clever/2107067

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Our certified, experienced, resilient, productive and committed Math Educators will be glad to be at your service. We make teaching and learning Mathematics fun for learners, we expose the simplicity and beauty of Mathematics to our learners, and mentor them to appreciate and love Mathematics. Communicate us to mentor/educate you Mathematics better online at affordable tuition.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2106557

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tan30 = a/(2√(3)) a = 2 units. b = (2√(3)-2) units. tan30 = c/(2√(3)-2) c = ⅓(6-2√(3)) units. d = 2√(3)-⅓(6-2√(3)) d = ⅓(6√(3)-6+2√(3)) d = ⅓(8√(3)-6) units. It implies; Area Blue exactly in square units is; ½(2√(3))²*sin60-½(⅓(8√(3)-6))²*sin60 = 3√(3)-⅓(19√(3)-24) = ⅓(9√(3)-19√(3)+24) = ⅓(24-10√(3)) square units.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2106145

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Shaded/Area Blue is; 2(area sector with radius 4 unit and angle (180-2atan(½))° - area triangle with two side 4 unit respectively, and angle (180-2atan(½))°) + 2(area sector with radius 2 unit and angle (180-2atan(2))° - area triangle with two side 2 unit respectively, and angle (180-2atan(2))°) + 4(area sector with radius 2 unit and angle (2atan(2))° - area triangle with two side 2 unit respectively, and angle (2atan(2))°). = 2((180-2atan(½))×16π÷360) - ½(16sin(180-2atan(½)))) + 2((180-2ata...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2105685

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Sir Mike Ambrose is the author of the question. Let the square side be 2 units. Area Square is; 2² = 4 square units. Calculating Area Yellow. (2-a)²+1 = a²+4 4-4a+a²+1=a²+4 a = ¼ unit. b² = 1+(65/64)-2*⅛(√(65))cos(atan2+atan(3/2)) b = ⅛√(193) units. (b/sin(atan2+atan(3/2))) = ((⅛√(65))/sinc) c = asin(7√(193)/193)° c = 30.25643716353° d = acos(7√(193)/193)° d = 59.74356283647° e² = 4+(193/64)-(2*2√(193)/8)cos(acos(7√(193)/193)) e = (15/8) units. (15/8sin(acos(7/√(193)))) = (√(193)/8si...
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