Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2858095

Sir Mike Ambrose is the author of the question. Area green total, in square unit decimal form is; Area triangle with height 6sin(atan(3/5)) units and base 6cos(atan(3/5)) units + Area triangle with height 4 units and base 4tan(atan(2/5)) units. = ½*6sin(atan(3/5))*6cos(atan(3/5)) + ½*4*4tan(atan(2/5)) = 7.94117647059 + 3.2 = 11.1411764706 square units.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2858083

Area red/Area Blue = ⅓ Please, move the above question left/right one time to review the solution of the question. Thank you kindly.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2857487

3^(x) - √(3)^(x)*√(3)^(6) = -162 3^(x) - 3^(x/2)*3^(3) = -162 Let p be 3^(x) p - 27p^(½) + 162 = 0 p-18p^(½)-9p^(½)p+162 = 0 p^(½)(p^(½)-18)-9(p^(½)-18) = 0 (p^(½)-18) = 0 or (p^(½)-9) = 0 p = 324 or p = 81 And p is 3^(x) It implies; 3^(x) = 324 or 3^(x) = 81 x = log(324)/log(3) or x = 4 Therefore; x = log(324)/log(3) or x = 4 x = 5.26185950714 or x = 4

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2857013

Let 1 unit be AB = AC. a = 12+24 a = 36° a is angle ABC = angle ACB. b = 180-2(a) b = 180-72 b = 108° b is angle BAC. c = b-6 c = 108-6 c = 102° c is angle CAD. d = 180-12-6 d = 162° d is angle ADB. It implies; (1/sin162) = (e/sin12) e = 0.6728163648 units. e is AD. f² = 0.6728163648²+1²-2*0.6728163648*1cos102 f = 1.3162274259 units. f is CD. Therefore, the required angle, x is; (1.3162274259/sin102) = (0.6728163648/sinx) x = 30° x is angle ACD.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2856718

Notice; Hexagon Area = 24√(3) square units. Calculating hexagon side length. Let it be a. (6a²)/(4tan30) = 24√(3) ½(3√(3))a² = 24√(3) 3a² = 48 a = 4 units. Equation of the curve is; y = ½(x²) ------ (1). sin60 = b/4 b = 2√(3) units. cos60 = c/4 c = 2 units. Gradient = ((4√(3)+2)-(2√(3)+2))/(2-4) Gradient = -√(3) (y-(4√(3)+2))/(x-2) = -√(3) y = -√(3)x+6√(3)+2 ---- (2). Equation (1) and (2). ½(x)² = -√(3)x+6√(3)+2 x = 3.53906 y = ½(3.53906)² y = 6...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2856696

Let the radius of the inscribed half circle be 1 unit. Area rectangle is; 2*1 = 2 square units. Calculating Shaded Area as a single fraction.. It is; ½(1*2) - 1² + ¼(1)²π - ((180-2atan(½))π*1²/360) + (0.5*1²sin(180-2atan(½))) = 1-1+¼(π)-(π(180-2atan(½))/360)+⅖ = (π/4)+⅖-(π(180-2atan(½))/360) = ((5π+8)/20)-(π(180-2atan(½))/360) = (90π+144-180π+2πatan(½))/360 = (144-90π+2πatan(½))/360 square units. Therefore; Area Shaded ÷ Area Rectangle as a single fraction is; ((...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2855166

Sir Mike Ambrose is the author of the question. The side of area green, inscribed square is; Let it be x. Therefore; 1.11496246101x + 0.82101781219x = 27.3672604063 1.9359802732x = 27.3672604063 x = 14.1361256544 cm Therefore; Exact perimeter of green area in decimal cm is; 4(14.1361256544) = 56.5445026176 cm

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2855149

a² = 10²+16²-2*10*16cos120 a = 2√(129) units. Where a is length AC. (3√(129)/sin120) = (16/sinb) b = 37.58908946897° c = 90-b c = 52.41091053103° d = 60-b d = 22.41091053103° e = 90-d e = 67.58908946897° f = 90-60 f = 30° cos37.58908946897 = g/10 g = 7.92405815693 units. i = 30+37.58908946897 i = 67.58908946897° tan67.58908946897 = j/7.92405815693 j = 19.2148198619 units. Where j is the radius of the arc. sin67.58908946897 = 19.2148198619/k k = 20....

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2853602

Sir Mike Ambrose is the author of the question. Let the two equal marked lengths of triangle ABC be 2 units. Therefore; Area triangle ABC is; Area triangle with height 5.75877048314 units and base (5.75877048314sin20) units. = 0.5*5.75877048314*5.75877048314sin20 = 5.67128181961 space units. Area purple is; Area triangle with height 4 units and base (1.11985686148sin28.334490436) units. = 0.5*4*1.11985686148sin28.334490436 = 1.06300877373 space units. It implies;...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2853585

Sir Mike Ambrose is the author of the question. Let AC be 1 unit. Area smaller pentagon is; ½(5)*(1/(2tan(36))) = 1.72047740059 square units. a² = 1²+0.5²-cos108 a = 1.24860602048 units. Where a is CD. (1.24860602048/sin108) = (0.5/sinb) b = 22.38617755917° c = 108-22.38617755917 c = 85.61382244083° Calculating Area E. It is; 0.5*0.5*0.5*1.24860602048sin22.38617755917 = 0.05944103227 square units. (a) Area E ÷ Area Smaller Pentagon to 3 decimal places is;...

You Searched for "post"

2242 result found.

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

OnlineEdumath

Socials

Useful Tags

Quick Links

Reach Us

Safety and Abuse Reporting

Thanks for being awesome!

Are you sure you want to report abuse against this website?

Search

You Searched for "post"

2242 result found.

Subscribe to our mailing list for latest updates.

Safety and Abuse Reporting

Thanks for being awesome!

Are you sure you want to report abuse against this website?