Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2428197

Let the ascribed regular pentagon side length be 1 unit. a = ⅕(180(5-2)) a = 108° a is the single interior angle of the ascribed and the smaller inscribed regular pentagon. b = ½(180-108) b = 36° c = 108-36 c = 72° d = 180-108 d = c = 72° e = 180-72-72 e = b = 36° Let f be the side length of the smaller inscribed regular pentagon. g = (1-f) units. Calculating f. cos72 = (0.5(1-f))/f 0.6180339887f = 1-f 1.6180339887f = 1 f = 1/1.6180339887 f = 0.6180339887 units. Again, f is the side...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2428076

Let the side length of the regular hexagon be 2 units. a = ⅙(180(6-2)) a = 120° a is the single interior angle of the regular hexagon. b² = 2²+1²-2*2*1cos120 b = √(7) units. b = 2.6457513111 units. (2.6457513111sin120) = (1/sinc) c = 19.1066053509° d = 120-c d = 120-19.1066053509 d = 100.8933946491° Therefore, e is; e = 0.5*√(7)*2cos100.8933946491 e = √(7)cos100.8933946491 e = 2.5980762114 square units. e is the area of green plus orange inscribed plane shape (inscribed scalene triangle)...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2427217

a² = 10²+5² a = √(125) a = 5√(5) units. a = 11.1803398875 units. a is the side length of the square. tanb = 10/5 b = atan(2)° c = atan(1/2)° d = 45-c d = (45-atan(1/2))° d = 18.4349488229° e = 45+d e = 45+(45-atan(1/2)) e = 45+18.4349488229 e = 63.4349488229° e = atan(2)° sine = f/10 sin(atan(2)) = f/10 f = 8.94427191 units cose = g/10 cos(atan(2)) = g/10 g = 4.472135955 units. h = a-g h = 5√(5)-4.472135955 h = 6.7082039325 units. j = f-g j = 8.94427191-4.472135955 j = 4.472135955 uni...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2426738

Let a be the radius of the inscribed semi circle. b = 2+4+a b = (6+a) cm. b is the diameter of the ascribed circle. c = ½(b) c = ½(6+a) cm. c is the radius of the ascribed circle. e = c-2 e = ½(6+a)-2 e = ½(6+a-4) e = ½(2+a) cm. Therefore, calculating a, radius of the inscribed semi circle. c² = a²+e² (½(6+a))² = a²+(½(2+a))² ¼(36+12a+a²) = a²+¼(4+4a+a²) 36+12a+a² = 4a²+4+4a+a² 0 = 4a²-8a-32 4a²-8a-32 = 0 a²-2a-8 = 0 Resolving the above quadratic equation via factorization approach to ge...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2426678

Calculating R, radius of the circle. It implies; 10²+11²-2*10*11cosa = 7²+8²+2*7*8cosa 221-220cosa = 113+112cosa 221-113 = 112cosa+220cosa 108 = 332cosa cosa = 108/332 a = acos(108/332) a = 71.016175615° b² = 10²+11²-2*10*11cos71.016175615 b = 12.2243091805 units. Therefore, R, radius of the circle is; sin71.016175615 = (0.5*12.2243091805)/R R = (0.5*12.2243091805)/sin71.016175615 R = 6.4637130226 units.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2426635

a = ⅙(180(6-2)) a = ⅙(180*4) a = 120° a is the single interior angle of the regular hexagon. b² = 2²+4²-2*2*4cos120 b = √(20+7) b = 2√(7) units. (2√(7)/sin120) = (2/sinc) c = 19.1066053509° d = 120-2c d = 120-2*19.1066053509 d = 81.7867892983° sin30 = e/4 e = 2 units. f = 2+e f = 2+2 f = 4 units. g² = 4²+4²-2*4*4cos120 g = √(32+16) g = √(48) g = 4√(3) units. Let r be the radius of the inscribed circle. Calculating r. sin60 = r/(4-r) r = 4sin60-rsin60...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2425871

Calculating x. a = 9+3 a = 12 units. Therefore the ascribed plane shape (quadrilateral or irregular quadrilateral) is an equilateral triangle of side length 12 units with a subtraction of a smaller equilateral triangle of side length 3 units. It implies; a² = x²+6² 12² = x²+6² x² = 144-36 x = √(108) x = 6√(3) units.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2425859

Notice. The ascribed triangle is equilateral. Let r be the radius of the inscribed half circle. Calculating r. sin60 = r/6 √(3)/2 = r/6 r = 3√(3) cm. It implies, area orange (inscribed semi circle) is; ½(r²)π = ½(3√(3))²π = ½(27)π = 13.5π cm² = 42.4115008235 cm²

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2423961

Let the side length of the regular octagon be 1 unit. a = ⅛(180(8-2)) a= ⅛(180*6) a = 135° a is the single interior angle of the regular octagon. 2b² = 1² b = √(1/2) b = ½√(2) units. c = 2b+1 c = 2(½√(2))+1 c = (√(2)+1) units. c is the side length of the regular triangle (equilateral triangle). d² = 2-2cos135 d = Let the side length of the regular octagon be 1 unit. a = ⅛(180(8-2)) a= ⅛(180*6) a = 135° a is the single interior angle of the regular octagon. 2b² = 1² b = √(1/2) b = ½√(2...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2423757

Calculating red length. Let r be the radius of the circle. sin30 = a/2 a = 1 unit. cos30 = b/2 b = √(3) units. Or b = ½√(2²+2²-2*2*2cos120) b = ½√(8+4) b = ½√(12) b = ½*2√(3) b = √(3) units. c = 2b c = 2√(3) units. d = 2+1+1 d = 4 units. r = ½(d) r = ½(4) r = 2 units. Again, r is the radius of the circle. e = 3r-a e = 3*2-1 e = 5 units. It implies, red length is; Let it be f. f² = 5²+b² f² = 25+√(3)² f² = 25+3 f = √(28) f = 2√(7) units. Again, f is the red length.

You Searched for "post"

2242 result found.

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

OnlineEdumath

Socials

Useful Tags

Quick Links

Reach Us

Safety and Abuse Reporting

Thanks for being awesome!

Are you sure you want to report abuse against this website?

Search

You Searched for "post"

2242 result found.

Subscribe to our mailing list for latest updates.

Safety and Abuse Reporting

Thanks for being awesome!

Are you sure you want to report abuse against this website?