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Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2535225

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Calculating h, height of the triangle. Notice! a+b = 28  a = (28-b) units. It implies; b² = 5²+h² h² = b²-25 --- (1). a² = 9²+h² And a = (28-b) units. (28-b)² = 81+h² h² = 784-56b+b²-81 h² = b²-56b+703 --- (2). Equating (1) and (2). b²-25 = b²-56b+703 56b = 728 b = 728/56 b = 91/7 b = 13 units. Therefore, h is; At (1). h² = b²-25 And b = 13 units. h² = 13²-25 h² = 169-25 h² = 144 h = √(144) h = 12 units.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2534730

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2(20x)+2(30x)+2x² = (x+30)(x+20) Where x is the radius of the inscribed circle. It implies; 40x+60x+2x² = x²+20x+30x+600 100x+2x² = x²+50x+600 x²+50x-600 = 0 Calculating x via completing the square approach. (x+25)² = 600+(25)² x+25 = ±√(600+625) x = -25±√(1225) x = -25±35 It implies; x = -25+35 x = 10 units. Again, x is the radius of the inscribed circle. Triangle height is; x+20 = 30 units. Triangle base is; x+30 = 40 units. Triangle area is; ½*base*hei...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2534184

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Let a be the side length of regular hexagon and the regular triangle (equilateral triangle). Calculating a. 0.5a²sin60 = √(3) ¼*√(3)a² = √(3) ¼(a²) = 1 a² = 4 a = 2 units. Again, a is the side length of the regular hexagon and the regular triangle (equilateral triangle). sin60 = b/2 b = √(3) units. b is R, radius of the arc. cos60 = c/2 c = 1 unit. (1/sind) = (√(3)/sin120) d = 30° c = 90-d c = 60° Calculating area B (yellow inscribed area). It implies; Area...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2534163

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Let AB be 1 unit. a = 180-12-36-18 a = 180-66 a = 114° a is angle AEB. (1/sin114) = (b/sin(18+36)) b = 0.885579352 units. b is AE. c = 180-6-36-42 c = 96° (1/sin96) = (d/sin(42+36)) d = 0.9835355112 units. Therefore, the required angle, x is; tanx = d/b x = atan(0.9835355112/0.885579352) x = 48°

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2533811

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a = ½(90) a = 45° tanb = 2/1 b = atan(2)° c = 90-b c = atan(½)° d = a-c d = (45-atan(½))° e = 180-2d e = 180-2(45-atan(½)) e = (90+2atan(½))° Therefore, length EF, let it be f, is; f² = 15²+15²-2*15*15cos(90+2atan(½)) f² = 450+360 f = √(810) f = 9√(10) units. f = 28.4604989415 units. Where f is length EF.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2532915

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a = 7-2.5 a = 4.5 units. b = 7+1 b = 8 units. tanc = 4.5/8 c = atan(4.5/8)° tand = 4.5/3 d = atan(4.5/3)° e = 180-c-d e = (180-atan(4.5/8)-atan(4.5/3))° (4/sin(180-atan(4.5/8)-atan(4.5/3))) = (f/sin(atan(4.5/8))) f = 1.9666643321 units. g = (atan(4.5/8)+atan(4.5/3))° (4/sin(180-atan(4.5/8)-atan(4.5/3))) = (h/sin(atan(4.5/3))) h = 3.3377381365 units. cos(atan(4.5/8)) = 4/j j = 4.5893899377 units. k = j-h k = 1.2516518012 units. It implies, area S (area red...

We are smart and clever!

https://onlineedumath.com/update/we-are-smart-and-clever/2532665

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Online Edumath Educators and Learners are Super Smart and Amazingly, Very Clever. Communicate us to mentor/teach/educate your child/children Mathematics online at affordable tuition, helping them become a lover of Mathematics, and also, a Mathematician. Call/WhatsApp: +2349076614992 or +2348152827445 Email: [email protected] [email protected] [email protected] Facebook Page: Online Edumath We are super smart and amazingly, very clever!

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2532632

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Calculating the red angle (angle DAM). Notice! ABCD is a regular quadrilateral (square). Let AB be 1 unit. tan60 = AB/BK BK = 1/√(3) BK = ⅓√(3) units. CK = 1-BK CK = ⅓(3-√(3)) units. tan30 = CK/CM CM = √(3)*⅓(3-√(3)) CM = ⅓(3√(3)-3) CM = (√(3)-1) units. DM = 1-CM DM = 1-(√(3)-1) DM = (2-√(3)) units. Therefore, the required angle, angle DAM is; Let it be x. tanx = DM/AD tanx = (2-√(3))/1 x = atan(2-√(3)) x = 15° Where x is the required angle, angle DAM...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2532093

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Calculating angle x. tana = ⅗ a = atan(⅗)° tan = ⅘ b = atan(⅘)° c = atan(5/4)° Therefore, the required angle x is; x = a+c x = atan(⅗)+atan(5/4) x = (atan(⅗)+atan(5/4))° x = 82.303948278°

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2532052

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Calculating the radius of the small inscribed pink circle. Let it be r. b = ⅕*180(5-2) b = 108° b is the single interior angle of the ascribed regular pentagon. c² = 10²+10²-2*10*10cos108 c = 16.1803398875 units. d = 108-36 d = 72° e = 90-72 e = 8° f²+(0.5*10)² = c² f² = 16.1803398875²-5² f = 15.3884176859 units. tan54 = g/5 g = 6.8819096024 units. Again, a is the radius of the bigger inscribed circle. h = 2g h = 13.7638192047 units. It implies; sin18= r/j...
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