Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2760268

Calculating the area of the inscribed regular pentagon. Let the single side length of the inscribed regular pentagon be x. 12²=2y²-2y²cos108 y = √(144/(2-2cos108)) y = 7.416407865 cm. Therefore; x = √(2(7.416407865)²-2(7.416407865)²cos36) x = 4.58359213501 cm. Therefore area inscribed regular pentagon is; (5*4.58359213501²)/(4tan(36)) = 36.1460548598 cm².

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2760251

Sir Mike Ambrose is the author of the question. Calculating letter k considering yellow area (trapezoid). It implies; Half the sum of two parallel length (54+4k²)/9 units and (54+10k²)/9 units, multiply height 3k units is equal yellow area. And yellow area = 117 square units. Therefore; ½(3k)(108+10k²)/9=117 7k³+54k-351=0 It implies; k = 3 unit. Therefore; Area green is; Area trapezoid with two parallel length 10 units and 6 units, and height 6 units. = ½(16)*6 =...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2759908

Shaded area is; Area semi circle with radius 7cm + Area rectangle with length 14 cm and width 7 cm - Area semi circle with radius 7cm. = ½(49π) + (14*7) - ½(49π) = 98 cm² Or Shaded Area is; Area rectangle with length 14 cm and width 7 cm. = 14*7 = 98 cm²

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2759119

Let a ber the radius of each of the two congruent circles. b = (a+29) units. b is the side length of the square. c² = 2*29² c² = 1682 c = 29√(2) units. Calculating a. It implies; a²+41² = c² a² = (29√(2))²+41² a² = 1682-1681 a = 1 unit.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2759076

Calculating green area. a² = 2²+2² a = √(8) a = 2√(2) units. sin30 = b/a ½ = b/(2√(2)) b = √(2) units. c²+b² = a² c²+√(2)² = (2√(2))² c² = 8-2 c = √(6) units. Area green is; (½*2*2)+(½*√(2)*√(6)) = (2+√(3)) square units. = 3.7320508076 square units. Calculating yellow area. d = -45+60 d = 15° tan15 = b/e e = (√(2)/tan15) units. e = 5.2779168675 units. sin15 = √(2)/f f = (√(2)/sin15) units. f = 5.4641016151 units. 2g² = f² 2g² = 29.8564064601 g =...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2759061

Let the base of the quadrilateral be 1 unit. a = -54-18+180 a = 108° (1/sin108) = ((b/sin18) b = 0.3249196962 units. Therefore, area B is; 0.5*1*0.3249196962sin54 = 0.131432778 square units. Calculating area A. c = -72-36+180 c = 72° (0.3249196962/sin36) = (d/sin72) d = 0.5257311121 units. e = -72+180 e = 108° f = -108-36 +180 f = 36° Area A is; 0.5*0.5257311121*0.5257311121sin108 = 0.131432778 square units. It implies; A ÷ B is; = 0.131432778...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2758906

Let c be the radius of the ascribed half circle. d² = 2c² d = √(2)c cm. d is the diameter of the inscribed half circle. e = ½(d) e = ½(√(2)c) cm. e is the radius of the inscribed half circle. Notice. a = 8 cm. 8² = f²+(√(2)c)² f = √(64-2c²) cm. g = 8+f g = (8+√(64-2c²)) cm. h = c+e h = (c+½(√(2)c)) cm. Calculating c. (8+√(64-2c²))² = (c+½(√(2)c))²+(½(√(2)c))² 64+16√(64-2c²)+64-2c² = c²+√(2)c²+½(c²)+½(c²) 128+16√(64-2c²) = 4c²+√(2)c² 128+16√(64-2c²) = 5.414...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2758862

13² = 20²+11²-2*20*11cosa 169 = 521-440cosa 440cosa = 521-169 cosa = 352/440 a = 36.8698976458° (13/sin36.8698976458) = (11/sinb) b = 30.5102374061° c = 180-a-b c = 112.6198649481° d = 90-a d = 53.1301023542° e = c-d e = 59.4897625939° cos53.1301023542 = f/11 f = 6.6 units. cos59.4897625939 = g/6.6 g = 3.3507692308 units. sin59.4897625939 = h/6.6 h = 5.6861538462 units. Therefore, area red is; 0.5gh = 0.5*3.3507692308*5.6861538462 = 9.5264946746 square...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2758856

a*3 = 2*6 a = 12/3 a = 4 units. b = ½(a+3) b = 3.5 units. c = ½(2+6) c = 4 units. d = c-2 d = 2 units. It implies, e, radius of the circle is; e² = 3.5²+2² e = √(16.25) e = ½√(65) units. e = 4.0311288741 units.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2758851

Sir Mike Ambrose is the author of the question. Let BC be 1 unit. Therefore; AB = 2 units. Area ACDE is; 3² = 9 square units. Area purple is; Area triangle with height 1.23931367493 units and base 0.3320730983 units + Area trapezoid with two parallel side 0.2679491924 units and 1.07179676983 units, and height 1 unit. = ½(1.23931367493*0.3320730983) + ½(0.2679491924+1.07179676983) = 0.2057713659+0.66987298112 = 0.87564434702 square units. Therefore; Area Square A...

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