Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2762591

Let the side length of the square be 2 units. tana = 2/1 c = atan(2)° d = 2a d = 2atan(2)° Calculating a. a² = 1²+1²-2*1*1cos(2atan(2)) a = 1.788854382 units. e = d-45 e = ((2atan(2))-45)° Calculating b. b² = 2-2cos((2atan(2))-90) b = 0.632455532 units. It implies; a÷b = 1.788854382÷0.632455532 = 2.8284271247

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2762397

Calculating length OB. a² = 6²+2² a = √(40) a = 2√(10) units. a is AC. tanb = 6/2 b = atan(3)° √(40)² = 2√(50)²-2√(50)²cosc 40 = 100-100cosc cosc = 6/10 c = acos(3/5)° c is angle AOC. d = ½(180-c) d = ½(180-acos(3/5)) d = 63.4349488229° d is angle OAC and angle OCA. e = b-d e = atan(3)-63.4349488229 e = 8.1301023542° e is angle OCB. Therefore, the required length, ? (OB) is; Let it be f. f² = √(50)²+2²-2*2√(50)cos8.1301023542 f = 5.0990195136 units. Ag...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2761578

Silver area is; 2(area rectangle with length 6 cm and width 3 cm - area quarter circle with radius 3 cm - area sector with radius 6 cm and angle 30° + area sector with radius 6 cm and angle 60° - area triangle with two length 6 cm each, and angle 60°). = 2((6*3)-¼(9π)-(30*36π÷360)+(60*36π÷360)-½(36sin60)) = 2(18-(9π/4)-3π+6π-9√(3)) = 2(18+(3π/4)-9√(3)) = (36+(3π/2)-18√(3)) cm² = 9.53547444414 cm²

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2761575

Sir Mike Ambrose is the author of the question. Let the length of the two congruent rectangles be x. Let their width be y. Therefore area rectangle is; x * y = xy square units. Area blue is; Area rectangle with length x units and width y units unit - 2(area triangle with height y units and base (y²/x) units). = xy - 2*½(y³/x) = (x²y-y³)/x square units. Area blue ÷ Area rectangle is; (x²y-y³)/x ÷ xy = (x²y-y³)/x²y = 1 - (y/x)² Notice; Considering two similar...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2761562

Let the length of the two congruent rectangle be 1 unit. Let the width be x. Therefore; 1 ~ (1+x) x ~ 1 Cross Multiply. 1/x = (x+1)/1 x²+x-1 = 0 (x+½)²=1+¼ x = -½±½√(5) Therefore; x ≠ -½(1+√(5)) units. x = ½(√(5)-1) units. Let alpha be y. Therefore; Tany = (1+x)/1 Tany = (1+x) And x = ½(√(5)-1) unit. Tany = ½(√(5)-1)+1 Tany = ½√(5)-½+1 Tany = ½√(5)+½ Tany = ½(1+√(5)) Therefore; Tany = Tan alpha = Golden Ratio

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2761548

Let the radius of the inscribed circle be r. Therefore the radius of the ascribed circle, R will be; R = √(4²+r²) R = √(16+r²) units. Therefore; Area yellow is; Area circle with radius √(16+r²) units - Area circle with radius r units. = π(√(16+r²))² - πr² = π(16+r²) - πr² = 16π + πr² - πr² = 16π square units.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2761531

Let the side length of the large square be 4 units. Therefore; The side length of the blue inscribed square is; 4-(4√(3)/3) = ⅓(12-4√(3)) units. Therefore; Side blue square : Side large square is; ⅓(12-4√(3)) : 4 = (12-4√(3))/12 = ⅓(3-√(3)) = 0.42264973081

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2761266

The width of the rectangle is; R units. The length of the rectangle is; = √((R+6)²-(R-6)²) = √(R²+12R+36-R²+12R-36) = √(24R) units. Therefore; √(24R) * R = 243 24R³ = 243² R³ = 2460.375 R = (2460.375)^(⅓) R = 13.5 units.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2760797

Please, move the above question left/right one time to review the solution. Thank you. Area Shaded/blue or purple is; = 8√(2)sin15 cm² = 2.92820323028 cm²

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2760466

Shaded area is; Area sector with radius 10 units and angle acos(0.7) - Area triangle with height √(51) units and base 7 units - area sector with radius 3 units and angle 81.37307344° - area sector with radius10 units and angle 17.2538531174° + area triangle with two sides length 10 units, and angle 17.2538531174° = (acos(0.7)*1))π÷360) - ½(√(51)*7) - (9π*81.37307344)/360 -(100π*17.2538531174)/360 + ½(100)sin17.2538531174 = 39.7699415092 - 24.9949994999 - 6.39102624298 - 15.0568272777 +...

You Searched for "delta state office ekrejeta house 2 zenith bank abraka delta state nigeria"

2452 result found.

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

OnlineEdumath

Socials

Facebook Page

Quick Links

Reach Us

Safety and Abuse Reporting

Thanks for being awesome!

Are you sure you want to report abuse against this website?

Search

You Searched for "delta state office ekrejeta house 2 zenith bank abraka delta state nigeria"

2452 result found.

Subscribe to our mailing list for latest updates.

Safety and Abuse Reporting

Thanks for being awesome!

Are you sure you want to report abuse against this website?