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A Kind And humble Call For Your Donation/Contribution/Support/Assistance Financially To Assist Us Purchase Website Subscription Plan

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“Hello! As a valued supporter of our cause, we kindly, nicely ask for your donation/contribution/support/assistance financially to help us purchase subscription plan to keep our website active as we continue making a positive impact. Your donation will go a long way in supporting our cause and efforts.” Our USD MiniPay Wallet Details. Name: Ephivbotor Ogheneovo Daniel  Phone/Wallet Number: +2349076614992 Our Naira (Nigeria Currency) Account Details. Holder Name: Ogheneovo Daniel Ephi...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3496461

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Sir Mike Ambrose is the author of the question.Let the side let of the square be 2 units.Therefore;Area square is;2²= 4 square units.It implies;Area R is;Area trapezoid with parallel sides 1 unit and 1.44948974279 unit, and height 2 unit - Area square with side 1 unit - Area triangle with base and height 1 unit respectively - Area sector with radius √(2) unit and angle 32.3335306935° - Area triangle with height √(2) unit and base 0.3178372452 unit= (½*2(1+1.44948974279)) - (1*1) - (½*1*1) - (32...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3490651

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Sir Mike Ambrose is the author of the question.Inscribed square single side length is;7.80540954246 cmArea green in cm² to 1 decimal place is;Area trapezoid with parallel sides 12 cm and 7.25948291225 cm, and height 12 cm - Area square with side 7.80540954246 cm - Area triangle with height 7.25948291225 cm and base 2.86780856615 cm.= ½*12(12+7.25948291225) - 7.80540954246² - ½*7.25948291225*2.86780856615= 115.556897474 - 60.9244181255 - 10.4094036408= 44.2230757077 cm²≈ 44.2 cm²

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3484848

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Sir Mike Ambrose is the author of the question.Calculating Area Shaded.y = 2^(x)P coordinate is;P(1, 2)dy/dx = 2^(x)In2For x = 1dy/dx = 2In2It implies;Q coordinate is;Q(0, (2-2In2))Therefore;Shaded area exactly in square units is;(Area under the curve at x = 0 and x = 1) - (Area trapezoid with parallel sides (2-2In2) unit and 2 unit, and height 1 unit).= (1/(In2)) - (½*1*(2+2-2In2))= (1/(In2)) - (2-In2)= (In2-1)²/In2 square units.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3478376

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Sir Mike Ambrose is the author of the question.Radius, r of the inscribed circle is;r = (3-√(3)) cmTherefore;Area purple exactly in square cm is;Area trapezium with parallel sides (3-√(3)) cm and 4 cm, and height 3+√(3) cm - 2(area triangle with height (3-√(3)) cm and base (3√(3)-3) cm).= ½*(3+√(3))(4+3-√(3)) - 2(½*(3-√(3))*(3√(3)-3))= (9+2√(3)) - (12√(3)-18)= (27-10√(3)) cm²

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3477389

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Sir Mike Ambrose is the author of the question. P(2, (16√(5)/5))Gradient of the curve at the tangent is;= 24/5√(5)Therefore;Gradient of the curve at the normal is;= -5√(5)/24It implies;Coordinate Q is;Q(4, (167√(5)/60))Therefore area R as a single fraction in square units is;(Area under the curve at x = 2 and x = 4) - (Area trapezium with parallel sides 167√(5)/60 units and 16√(5)/5 units, and height 2 units).= (24-⅓(8√(5))) - ½*2((167√(5)/60 )+(16√(5)/5))= 24 - ⅓(8√(5)) - (359√(5)/60)= (1440-5...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3470087

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Sir Mike Ambrose is the author of the question.At x = 0, y = 2.At y = 16, x = 1.Gradient of the curve at x = 1 or at the tangent is;dy/dx = 3In2*2^(3x+1)For x = 1dy/dx = 48In2Therefore coordinate Q is (x¹, 0).Calculating x¹.(0-16)/(x¹-1) = 48In2x¹= (3In2-1)/3In2It implies;Area Red exactly as a single fraction in its simplest form is;Area trapezoid with parallel sides 2 units and 16 units, and height 1 unit - Area triangle with height 16 units and base (1-((3In2-1)/3In2)) units.= (½*1(2+16)) - (...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3460521

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Sir Mike Ambrose is the author of the question.Calculating Area Green.Area green exactly in cm² is;Area ABCD - Area trapezoid with parallel sides (9-2√(3)) cm and (24√(3)-39) cm, and height 6 cm.= (54-6√(3)) - ½*6((9-2√(3))+(24√(3)-39))= (54-6√(3)) - 3(22√(3)-30)= 54-6√(3)-66√(3)+90= 144-72√(3)= 72(2-√(3)) cm²OrCalculating Area Green.Let a be BC.tan30 = 12/bb = 12√(3) cm.b is the height of the ascribed right-angled triangle.tan30 = a/cc = √(3)a cm.d = 6+cd = (6+√(3)a) cm.tan30 = e/(6+√(3)a)e =...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3458768

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Sir Mike Ambrose is the author of the question.Area blue total, exactly in cm² decimal is;Area trapezoid with parallel sides (80/7) cm and ((80/7)+21.4285714284) cm, and height 20 cm - Area trapezoid with parallel sides 20 cm and ((80/7)+12.2448979591) cm, and height (60/7) cm - Area triangle with height (80/7) cm and base 12.2448979591 cm.= (½*20((80/7)+((80/7)+21.4285714284))) - (½*(60/7)(20+((80/7)+12.2448979591))) - (½*(80/7)*12.2448979591)= 442.857142855 - 187.172011662 - 69.9708454806= 18...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3401118

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Sir Mike Ambrose is the author of the question.Calculating Area Green.Area green exactly in cm² is;Area ABCD - Area trapezoid with parallel sides (9-2√(3)) cm and (24√(3)-39) cm, and height 6 cm.= (54-6√(3)) - ½*6((9-2√(3))+(24√(3)-39))= (54-6√(3)) - 3(22√(3)-30)= 54-6√(3)-66√(3)+90= 144-72√(3)= 72(2-√(3)) cm²OrCalculating Area Green.Let a be BC.tan30 = 12/bb = 12√(3) cm.b is the height of the ascribed right-angled triangle.tan30 = a/cc = √(3)a cm.d = 6+cd = (6+√(3)a) cm.tan30 = e/(6+√(3)a)e =...

3 result found.

media video Class with Adesuwa, year 6 pupil.

Class with Adesuwa, year 6 pupil.

media video Find Blue Area

Find Blue Area

media video Finding Prime Numbers

Finding Prime Numbers

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Our Smart and Clever Learners

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1. Adesuwa Amadin (year 8), England. 2. Oghosa Amadin (year 10), England. 3. Manasseh Desmond (Senior Secondary 2), Nigeria. 4. Oghenemano Ejemah (Senior  Secondary 2), Nigeria. 5. Ogheneruno Ephivbotor (Senior Secondary 3), Nigeria. 6. Prince Iyobhebhe (year 7), England. 7. Ogheneruemu Ephivbotor (Junior Secondary 2), Nigeria. 8. Oghenezino Ejemah (Junior Secondary 2), Nigeria. 9. Efemena Ephivbotor (Senior Secondary 1), Nigeria. 10. Oghenemena Ejemah (Primary 4), Nigeria. 11. Martins Ephivboto...

Short Videos of Our Teaching and Learning Activities

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Please, highlight and open/browse the links below to view videos of our teaching and learning activities. Thank you. Video 1. Class with Adesuwa (year 5) 27/06/2023 https://www.facebook.com/100003984568865/posts/pfbid02VGXZkxZYksDaBSZXhbkir8GKETEiU2fCQobAVZE4Yv84HRaQ3NL1XvAMTRTxsNs3l/?app=fbl Video 2. Class with Zino and Ruemu (year 4) 27/06/2023 https://www.facebook.com/100003984568865/posts/pfbid038EyeWYY8Du4XgbEb7mbz33DS7XAvYWjXTwrE6HRfC4qpFTqCX6YVFYmnCeDBfEWHl/?app=fbl Video 3. Class with A...
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