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Our certified, experienced, resilient, productive and committed Math Educators will be glad to be at your service. We make teaching and learning Mathematics fun for learners, we expose the simplicity and beauty of Mathematics to our learners, and mentor them to appreciate and love Mathematics. Communicate us to mentor/educate you Mathematics better online. We are smart and clever.

We are smart and clever!

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Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/1882433

9 = 8-8cosa 8cosa = -1 a = acos(-1/8) a = 97.18075578146° Therefore; a• = 180-a a• = 180-97.18075578146 a• = 82.81924421854° b = ½(180-82.81924421854) b = 48.59037789073° c = ½(48.59037789073) c = 24.29518894536° Where c is alpha. sin24.29518894536 = d/4 d = 1.64575131106 cm. cos24.29518894536 = e/4 e = 3.64575131106 cm. f = 90-24.29518894536 f = 65.70481105464° Red area is; 0.5*1*1.64575131106sin65.70481105464 = ¾ cm² Blue area is; 2(0.5*3.64575131106*1.64575131106)-(¾) = 6-(3/4)...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/1881678

a = acos(3/5) Where a is angle GCA. tan(acos(3/5)) = b/3 b = 4 units. Where b is AG. c = atan(⅔) Where c is angle GBE. d = 180-acos(3/5)-atan(⅔) d = 93.17983011986° Where d is angle BEC. (6/sin93.17983011986 ) = (e/sin(acos(⅗))) e = 4.80740170062 units. Where e is BE. Area Parallelogram BCDE is; 2(area triangle with height 4.80740170062 units and base 6sin(atan(⅔)) units. = 2(0.5*4.80740170062*6sin(atan(⅔))) = 16 square units.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/1881048

Let the inscribed square side be a. tan60 = a/b a = √(3)b cm. Where b is BS = CR It implies; b+√(3)b+b = 10 (2+√(3))b = 10 b = 10(2-√(3)) cm. Therefore; a = √(3)*10(2-√(3)) a = 10(2√(3)-3) cm. a = 4.64101615138 cm. sin60 = 10(2√(3)-3)/c c = 20(2-√(3)) cm. Where c is CQ. d² = 10²+(10(2-√(3)))²-20*10(2-√(3))cos60 d = 8.96575472168 cm. Where d is AS. (8.96575472168/sin60) = (10(2-√(3))/sine) e = 15° Where e is angle PAS. f = 180-60-15 f = 105° Where f is angle BSA. g = 105-90 g = 15° Whe...

We are smart and clever!

https://onlineedumath.com/update/we-are-smart-and-clever/1880147

Our certified, experienced, resilient, productive and committed Math Educators will be glad to be at your service. We make teaching and learning Mathematics fun for learners, we expose the simplicity and beauty of Mathematics to our learners, and mentor them to appreciate and love Mathematics. Communicate us to mentor/educate you Mathematics better online. We are smart and clever.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/1880138

xy = 40 ------ (1). b = 4+x-5 b = x-1 y(x-1) = 20 ------ (2). At (1) x = 40/y ------ (3). Notice; y is the length or base of the rectangle. Substituting (3) in (2) to get y. y((40/y)-1) = 20 40-y = 20 y = 40-20 y = 20 cm.

We are smart and clever!

https://onlineedumath.com/update/we-are-smart-and-clever/1879888

Screenshot of today's teaching and learning activities with arithmetical, super smart and clever Oghenevwarhe. Oghenevwarhe is in year 8. Educator: Mr. Daniel

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/1879482

Making a circle to ascribe A, B, C and E quadrilateral with the circumference of the circle cutting across A, B, C and E. Therefore; Angle ABC will be; ½(240) = 120° Parallelogram ABCD height is; Let it be x. sin60 = x/4 ½√(3) = x/4 x= 2√(3) cm. Parallelogram ABCD Area is; 6*2√(3) = 12√(3) cm²

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/1879295

Let the inscribed square side be a. tan60 = a/b a = √(3)b cm. Where b is BS = CR It implies; b+√(3)b+b = 10 (2+√(3))b = 10 b = 10(2-√(3)) cm. Therefore; a = √(3)*10(2-√(3)) a = 10(2√(3)-3) cm. sin60 = 10(2√(3)-3)/c c = 20(2-√(3)) cm. Where c is CQ. d² = 10²+(10(2-√(3)))²-20*10(2-√(3))cos60 d = 8.96575472168 cm. Where d is AS. (8.96575472168/sin60) = (10(2-√(3))/sine) e = 15° Where e is angle PAS. f = 180-60-15 f = 105° Where f is angle BSA. g = 105-90 g = 15° Where g is angle PSA. ta...

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We are smart and clever!

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Mathematics Question and Solution

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Mathematics Question and Solution

We are smart and clever!

Mathematics Question and Solution

We are smart and clever!

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