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Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/1837637

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Let AB = x PB = x/4 Therefore; a = x - (x/4) a = (3x/4) units. b² = x²+(3x/4)² b = √(x²+(3x/4)²) units. c = (x-4) units. It implies that; ½(x*(3x/4)) + ½(4*√(x²+(3x/4)²)) + ½(4*(x-4)) + (4*4) + ½((x/4)+4)*(x-4) = x² ⅛(3x²) + 2√(x²+(3x/4)²) + 2(x-4) + 16 + ½(¼(x+16))(x-4) = x² 2√(x²+(3x/4)²) + 2x + 8 + ⅛(x²+12x-64) = ⅛(5x²) 16√(x²+(3x/4)²)+16x+64+x²+12x-64 = 5x² 16√(x²+(3x/4)²)+28x = 4x² Dividing through by 4 4√(x²+(3x/4)²)+7x = x² 16(x²+(9x²/16)) = x⁴-14x³+49x² 16(25x²/16) = x⁴-1...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/1836467

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a = 15-11.25  a = 3.75 m. b = atan(3/3.75)° c = 90-atan(3/3.75) c = 51.34019174591°  Calculating Length CD. tan(51.34019174591) = 15/CD CD = 15/tan(51.34019174591)  CD = 12 m.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/1833746

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Red Area is; 7(area square with side 1 unit) - Area triangle with base 1 unit and height 4 units - Area square with side 1 unit - Area triangle with height and base 1 unit respectively. = 7(1*1) - 0.5(1*4) - (1*1) - 0.5(1*1) = 7 - 2 - 1 - 0.5 = 3.5 square units.

We are smart and clever!

https://onlineedumath.com/update/we-are-smart-and-clever/1833740

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Screenshot of yesterday's teaching and learning activities with some of our very talented, smart and clever learners; Prince (year 4), Oghenezino (year 4) and Ogheneruemu (year 4). Educator: Mr. Daniel We are smart and clever!

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/1831670

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a = 0.5(90-60) a = 15° cos15 =4/b b = 4.14110472164 cm. Where b is the side length of the inscribed regular triangle purple area. Purple area is; Area triangle with height 4.14110472164 cm and base 4.14110472164sin60 cm = 0.5*4.14110472164*4.14110472164sin60 = 7.4256258422 cm²

We are smart and clever!

https://onlineedumath.com/update/we-are-smart-and-clever/1831030

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Screenshot of today's teaching and learning activities with some of our very amazing, smart and clever learners; Ogheneruona (year 10), Ogheneruno (year 9), Oghenevwarhe (year 8), Destiny (year 10) and Oghenemano (year 8). Educators: Mr. Daniel, Mr. Ogheneovo We are smart and clever!

We are smart and clever!

https://onlineedumath.com/update/we-are-smart-and-clever/1830457

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Our Certified, Experienced, Hardworking, Resilient and Productive Mathematics Educators will be happy to be at your service to educate your learner/learners become a lover of Mathematics, and a better Mathematician at affordable tuition. We make the necessary Mathematics Curriculum/Scheme of work a priority as we mentor learners experience the beauty of Mathematics. Be nice to communicate us; Call/WhatsApp: +2349076614992 +2348152827445 Email: [email protected] educators@onli...

We are smart and clever!

https://onlineedumath.com/update/we-are-smart-and-clever/1829490

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Our Resilient, Hardworking and Productive Educators make teaching and learning Mathematics fun for learners, we mentor learners experience the beauty of Mathematics. Communicate us to mentor/coach your child/children love Mathematics, and become a better Mathematician at affordable tuition. We are smart and clever!

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/1829068

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(2√(2)/sin135) = (√(2)/sina) a = 20.70481105464° b = 180-20.70481105464-135 b = 24.29518894536° (c/sin24.29518894536) = (2√(2)/sin135) c = 1.64575131106 units. Where c is the height of the yellow inscribed trapezoid. (2√(2)/sin45) = (√(2)/sind) d = 20.70481105464° e = 180-20.70481105464-45 e = 114.29518894536° (2√(2)/sin45) = (f/sin114.29518894536) f = 3.64575131106 units. Where f is the base parallel length of the inscribed yellow trapezoid. g = 90-20.70481105464 g = 69.29518894536°...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/1826777

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a² = 11*11+10*10-2*11*10cos50 a = 8.92113926968 cm. (8.92113926968/sin50) = (10/sinb) b = 59.16920318624° c = 180-50-59.16920318624 c = 70.83079681376°  d = 0.5a d = 4.46056963484 cm. e² = 4.46056963484²+5.5²-2*4.46056963484*5.5cos59.16920318624 e = 5 cm. (5/sin59.16920318624) = (5.5/sinf) f = 70.83079681376° g² = 4.46056963484²+5²-2*4.46056963484*5cos70.83079681376 g = 5.5 cm. (5.5/sin70.83079681376) = (5/sinh) h = 59.16920318624° i = 180-59.16920318624-70.83079681376 i = 50° (j/tan...
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