You Searched for "post"

2242 result found.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2557552

mathematics-question-and-solution_1717252461CpgZQJ.jpeg
√(x-2)-√(x+3) = 1 x-2=(1+√(x+3))² x-2=1+2√(x+3)+x+3 -6=2√(x+3) -3=√(x+3) 9=x+3 x=6. Checking accuracy. √(6-2)-√(6+3)=? √(4)-√(9)=? ±2-±3=? ±2+3=? +2+3≠1 Therefore; -2+3=1

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2557528

mathematics-question-and-solution_1717251396Q71pWh.jpeg
Let the single side length of the ascribed square be 2 unit. Therefore area of the ascribed square is; 4 square unit. Calculating shaded area (area yellow). It will be; Area square of single side length 2 unit - area circle of radius 1 unit + 8(area quarter of radius ½√(2) unit - area triangle of height and base ½√(2) unit respectively). = 4 - π + 8(¼(½√(2))²π - ½(½√(2))² = 4 - π + 8(⅛(π) - ¼) = 4 - π + π - 2 = 2 square unit. Therefore shaded fraction is; Area yellow (shaded area) ÷ Ar...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2556794

mathematics-question-and-solution_1717222100BgSYlS.jpeg
Calculating Area Red/Area Yellow. Let R, radius of the equal circles be 1 unit. Area Yellow is; 2(2(area sector with radius 1 unit and angle 60°) - area regular triangle with side length 1 unit) = 2(2(60π/360)-½*sin60) = 2(⅓(π)-¼(√(3))) = ⅔(π)-½√(3) = ⅙(4π-3√(3)) square units. = 1.2283696986 square units. Area Red is; Area circle with radius 1 unit - Area yellow. = π-⅙(4π-3√(3)) = ⅙(6π-4π+3√(3)) = ⅙(2π+3√(3)) square units. = 1.913222955 square units. Therefore,...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2556760

mathematics-question-and-solution_1717219916UOK8H3.jpeg
Notice! AC = 7+7 AC = 14 units. It implies; 14² = 2a² a² = ½(196) a = √(98) a = 7√(2) units. a is the side length of square ABCD. Therefore, shaded area yellow is; Area square with side length 7√(2) units - 2(area quarter circle with radius 7 units). = (7√(2)*7√(2))-2(¼*7*7π) For π = (22/7) = 98-½(22*7) = 98-77 = 21 square units.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2556640

mathematics-question-and-solution_1717210653agGCZS.jpeg
sin30 = 10/a a = 20 units. a is the side length of the square. sin30 = b/10 b = 5 units. Therefore; Area Yellow is; Area triangle with height 20 units and base 5 units. = ½*20*5 = ½(100) = 50 square units.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2556618

mathematics-question-and-solution_1717209028iFYhak.jpeg
a² = 3²+5²-2*3*5cos60 a = √(19) units. a = 4.3588989435 units. a is AC. b² = 2²+1²-2*2*1cos60 b = √(3) units. b = 1.7320508076 units. b is CD. (√(19)/sin120) = (√(3)/sinc) c = 20.1283062882° c is angle CAD. d = 60-c d = 39.8716937118° d is angle ACD. It implies, Area ABCD (area inscribed yellow cyclic quadrilateral) is; Area triangle with height 5 units and base 3sin60 units + Area triangle with height √(19) units and base √(3)sin39.8716937118 units. = 0.5*5*3sin60...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2556537

mathematics-question-and-solution_17172032278OPuc7.jpeg
Calculating x. (a+30)*x = (30+15)(30+15) x = 45²/(a+30) --- (1). a*x = 15*15 a = 225/x --- (2). Therefore, Substituting (2) in (1) to get x. x = 45²/((225/x)+30) x = 2025÷(225+30x)/x x = 2025x/(225+30x) 225+30x = 2025 30x = 2025-225 30x = 1800 x = 60 units.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2556508

mathematics-question-and-solution_1717201184K9ZOx8.jpeg
5² = 2a² a² = ½(25) a = √(½(25)) cm. a = √(12.5) cm. b = 5-a b = (5-√(½(25))) cm. b = (5-√(12.5)) cm. It implies, blue area is; ½(b²) = ½(5-√(½(25)))² = ½(5-√(12.5))² = ½(25-10√(12.5)+12.5) = ½(37.5-10√(12.5))  = (18.75-5√(12.5)) cm² = 1.0723304703 cm²

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2556293

mathematics-question-and-solution_17171893616tIG2s.jpeg
Sir Mike Ambrose is the author of the question. Let the square side be x unit. Calculating x. x² = (x-4)² + ((x/2)+√((x²/4)-16)² 320 = 32x x = 10 units. Therefore; Shaded Area is; Area triangle with height 8 units and base 4 units - Area sector with radius 10 units and angle 2asin(√(5)/5) + Area triangle with height 10 units and base 10sin(2asin(√(5)/5)) units. = ½*8*4 - (2asin(√(5)/5)*10*10*π÷360) + ½*10*10sin(2asin(√(5)/5)) = 16 - 46.36476090008 + 40 = 56 - 46.3647609...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2555779

mathematics-question-and-solution_1717168656Oz54l9.jpeg
a² = 3²+4² a = √(25) a = 5 cm. a is the radius of the quarter circle. Let r be the radius of the inscribed blue circle. Calculating r. b = (3+r) cm. c = (5-r) cm. It implies; (5-r)² = (3+r)²+r² 25-10r+r² = 9+6r+r²+r² r²+16r-16 = 0 Resolving the above quadratic equation via completing the square approach to get r, radius of the inscribed blue circle. (r+8)² = 16+(8)² (r+8)² = 80 r = -8±√(80) r = -8±4√(5) It implies; r = (4√(5)-8) cm. r = 0.94427191 cm....
WhatsApp Google Map
✕

Safety and Abuse Reporting

Thanks for being awesome!

We appreciate you contacting us. Our support will get back in touch with you soon!

Have a great day!

Are you sure you want to report abuse against this website?

Please note that your query will be processed only if we find it relevant. Rest all requests will be ignored. If you need help with the website, please login to your dashboard and connect to support

Cancel Confirm