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Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2337958

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Notice. Rectangle width is 4 units. a = 4-1 a = 3 units. tanb = ½ b = atan(⅓)° c = 2b c = 2atan(⅓)° d = 90-c d = (90-2atan(⅓))° tan(½d) = 2/e tan(0.5(90-2atan(⅓))) = 2/e e = 2/tan(0.5(90-2atan(⅓))) e = 4 units. f = e+2 f = 4+2 f = 6 units. f is the length of the rectangle. It implies; Area Rectangle is; Length*Width = 6*4 = 24 square units.

We are smart and clever!

https://onlineedumath.com/update/we-are-smart-and-clever/2337411

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Above is screenshot of teaching and learning activities with Adesuwa. She is one of Online Edumath learners, hardworking, resilient and an amazing year 6 Mathematician. The Management and Educators of Online Edumath are very proud of you, Adesuwa. Adesuwa is super smart and amazingly, very clever!

We are smart and clever!

https://onlineedumath.com/update/we-are-smart-and-clever/2336816

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Online Edumath Educators and Learners are Super Smart and Amazingly, Very Clever. Communicate us to mentor/teach/educate your child/children Mathematics online at affordable tuition, helping them become a lover of Mathematics, and also, a Mathematician. Call/WhatsApp: +2349076614992 or +2348152827445 Email: [email protected] [email protected] [email protected] Facebook Page: Online Edumath We are super smart and amazingly, very clever!

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2336300

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(2√(2)/sin135) = (√(2)/sina) a = 20.70481105464° b = 180-20.70481105464-135 b = 24.29518894536° (c/sin24.29518894536) = (2√(2)/sin135) c = 1.64575131106 units. Where c is the height of the yellow inscribed trapezoid. (2√(2)/sin45) = (√(2)/sind) d = 20.70481105464° e = 180-20.70481105464-45 e = 114.29518894536° (2√(2)/sin45) = (f/sin114.29518894536) f = 3.64575131106 units. Where f is the base parallel length of the inscribed yellow trapezoid. g = 90-20.70481105464 g = 69.29518894536°...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2336202

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Red Area is; 7(area square with side 1 unit) - Area triangle with base 1 unit and height 4 units - Area square with side 1 unit - Area triangle with height and base 1 unit respectively. = 7(1*1) - 0.5(1*4) - (1*1) - 0.5(1*1) = 7 - 2 - 1 - 0.5 = 3.5 square units.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2335668

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Let the radius of the inscribed yellow half circle be x. Calculating x. a = tan(3/4)° a is angle ABC. b = tan(4/3)° b is angle BAC. sin(atan(3/4)) = x/c c = (5x/3) c is OB. sin(atan(3/4)) = x/d d = (5x/4) d is OA. And AB is 5 units. It implies; OB+OA = 5 (5x/3)+(5x/4) = 5 20x+15x = 60 35x = 60 x = (60/35) units. x = (12/7) units. Notice, x is the radius of the inscribed yellow half circle. Area inscribed yellow half circle is; ½(12/7)²π = ½(144/49)π =...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2334873

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Let the inscribed blue square side length be x. It implies; Considering side lengths of similar right-angled triangle. 2 - x x - 6 Therefore; (2/x) = (x/6) Cross Multiply. x² = 12 Area Blue = 12 square units. Where √(12) = 2√(3) units is the side length of the inscribed blue square.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2332570

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Let the side of the green square be x. Therefore; x/(tan(atan¾)) + x + x/(tan(atan(4/3))) = 5 ⅓(4x) + x + ¼(3x) = 5 16x + 12x + 9x = 60 37x = 60 x = (60/37) units It implies; Area square green is; x² = (60/37)² = 3600/1369 square units. = 2.6296566837 square units.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2331178

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Let the three equal lengths be 1 unit. it implies; AB = BD = DE = 1 unit. a² = 1²+1²-2*1*1cos100 a = 1.5320888862 units a is AD. c = ½(180-100) c = 40° c is angle ADB. d = 180-40-40 d = 100° d is angle ADE. e² = 1.5320888862²+1²-2*1*1.53cos100 e = 1.969615506 units. e is AE. It implies; (1.969615506/sin100) = (1/sinf) f = 30° f is angle DAE. g = 40+30 g = 70° g is angle BAE Therefore, the required angle x (angle ACB) is; x+70+100 = 180 x = 180-170...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2328015

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r, radius of the quarter circle is; r = 8+6 r = 14 units. a = 180-60 a = 120° It implies; Calculating x, observing Cosine Rule. 14² = 6²+x²-2*6*xcos120 196 = 36+x²+6x x²+6x-160 = 0 Resolving the above quadratic equation via completing the square approach. (x+3)² = 160+3² x+3 = ±√(169) x = -3±13 It implies; x ≠ -3-13 x = -3+13 x = 10 units.
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