You Searched for "delta state office ekrejeta house 2 zenith bank abraka delta state nigeria"

2627 result found.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2747709

mathematics-question-and-solution_1726889283kxIjDY.jpeg
Let the side length of the regular octagon be 1 unit. a = ⅛*180(8-2) a = 135° a is the side length of the regular octagon. 2b² = 1² b = √(1/2) units. b = ½√(2) units. c = 1+b c = (1+½√(2)) units. c is the side length of the square. Therefore, alpha, let it be d, is; tand = b/c d = atan(½√(2)/(1+½√(2))) d = 22.5°

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2747687

mathematics-question-and-solution_17268870343bT0M8.jpeg
Sir Mike Ambrose is the author of the question. Area Blue exactly in cm² decimal form is; Area trapezoid with two parallel side (7√(2)+14) cm and 15.3137084989 cm, and height 18.4852813742 cm. = ½((7√(2)+14)+15.3137084989)*18.4852813742 = 362.433549545 cm²

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2747682

mathematics-question-and-solution_1726886665dULtzG.jpeg
Area green is; Area rectangle with length 18 units and width 16 units - Area triangle with height 12 units and base 16 units - Area semi circle with radius 10 units. = (18*16) - ½(16*12) - ½(100π) = 288 - 96 - 50π = (192-50π) square units.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2747671

mathematics-question-and-solution_1726885910AcUWuw.jpeg
Area Blue is; Area square with side length 4 cm - Area quarter circle with radius 4 cm + 2(area square with side length 2 cm). = (4*4)-(¼*4*4π)+2(2*2) = 16-4π+8 = 24-4π = 4(6-π) cm²

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2747362

mathematics-question-and-solution_1726863046p2P2MH.jpeg
Let a be the side length of the regular hexagon. sin30 = b/a b = ½(a) cm. c = 2b+a c = 2a cm. cos30 = d/a d = ½√(3)a cm. e = ½(162√(3)) cm² e = 81√(3) cm² e is half the area of the regular hexagon. Calculating a. ½(2a+a)*½√(3)a = 81√(3) ¼(3a²) = 81 a² = 27*4 a = 6√(3) cm. Again, a is the side length of the regular hexagon. sin30 = f/(6√(3)) f = 3√(3) cm. Let g be the radius of the inscribed circle. h = (3√(3)-g) cm. tan30 = g/(3√(3)-g) √(3)g = (3√(3)-g...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2746663

mathematics-question-and-solution_1726833940j7e5hQ.jpeg
a = ⅓(4L)-L a = ⅓(L) cm. tanb = L/(4L/3) b = atan(3/4)° 3/4 = c/(⅓(L)) c = ¼(L) cm. d = 180-45-atan(3/4) d = (45+atan(4/3))° It implies; ((4L/3)/sin(45+atan(4/3))) = (e/sin(atan(3/4))) e = 0.8081220356L cm. Calculating L. (0.5*0.8081220356L*(4L/3)sin45)-(0.5*(L/3)*(L/4) = 342/7 0.380952381L²-0.0416666667L² = 342/7 2.375L² = 342 L = 12 cm. Recall. e = 0.8081220356L And L = 12 cm. e = 0.8081220356*12 e = 9.6974644272cm. Therefore, red area exactly in dec...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2745936

mathematics-question-and-solution_1726793179Qbk91A.jpeg
Sir Mike Ambrose is the author of the question. Let the single side length of the square be 2 units. Therefore; Area square is; 2² = 4 square units. Calculating area green. It is; Area trapezium with two parallel side length (√(2)/6) units and (√(2)/3) units, and height (√(2)/2) units. = ½((√(2)/6)+(√(2)/3))*(√(2)/2) = ½((√(2)/2)*(√(2)/2)) = ½(½) = ¼ square units. It implies; Area Green ÷ Area Square Exactly is; ¼ ÷ 4 = 1/16

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2745916

mathematics-question-and-solution_1726791730lPRtiX.jpeg
White area is; Area sector with radius 6 cm and angle 120° + Area sector with radius 2 cm and angle 60° = (120*36π÷360) + (60*4π÷360) = 12π + ⅔(π) = ⅓(38π) cm²

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2745908

mathematics-question-and-solution_1726790896WY4yv1.jpeg
Green area is; Area circle with radius 5 units + 2(area sector with radius 20 units and angle 60°) - Area equilateral triangle with side 20 units. = π(5²) + 2(60÷360*20²π) - ½(20²)sin60 = 25π + ⅓(400π) - 100√(3) = ⅓(475π-300√(3)) square units. = 324.213756061 square units.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2745900

mathematics-question-and-solution_1726790375EmW21d.jpeg
Let the radius of the inscribed circle be r. The radius of the semi circle is 5 units. Therefore; (2r)² + r² = 5² 4r² + r² = 25 r = √(5) units. Therefore shaded area/area blue is; Area semi circle with radius 5 units - Area circle with radius √(5) units. = ½(25π) - π√(5)² = ½(25π) - 5π = ½(25π-10π) = ½(15π) square units.
WhatsApp Google Map
✕

Safety and Abuse Reporting

Thanks for being awesome!

We appreciate you contacting us. Our support will get back in touch with you soon!

Have a great day!

Are you sure you want to report abuse against this website?

Please note that your query will be processed only if we find it relevant. Rest all requests will be ignored. If you need help with the website, please login to your dashboard and connect to support

Cancel Confirm