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Mathematics Questions and Solution

https://onlineedumath.com/update/mathematics-questions-and-solution/3032283

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Sir Mike Ambrose is the author of the question. Let the side of the inscribed square be 2 units. Therefore; Area S is; Area triangle with two side 1.03528 units and 0.53589838486 units, and angle 45° = 0.5*1.03528*0.53589838486sin45 = 0.1961531464 space units. Area R is; Area triangle with two side (2√(2)-2) units and 0.65961372961 units, and angle 72.367664609° = 0.5*(2√(2)-2)*0.65961372961sin72.36766460 = 0.26038499708 space units. Area T is; Area sector with radius 2√(2) units a...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3030094

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Sir Mike Ambrose is the author of the question. P coordinate is; P(3, 9) Q coordinate is; Q(2, 5), Q(3, 5) It implies; Shaded area exactly in its square units simplest form is; (Area under the curve at x = 2 and x = 3) - (Area trapezoid with parallel sides ⅓(23) units and 9 units, and height 1 unit). = (8+ln(81/16)) - ½((23/3)+9) = (8+ln(81/16))-½(50/3) = (8+ln(81/16))-⅓(25) = (ln(81/16)-⅓) square units. = 1.2885270991 square units.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3028425

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Sir Mike Ambrose is the author of the question. Calculating the circle's radius, r. 21r + 15r + 12√(2)r = 21*12√(2)sin45 (36+12√(2))r = 252 r = 252/(36+12√(2)) cm r = 3(3-√(2)) cm It implies; The exact area of the Circle in terms of π square cm is; π(9-3√(2))² = 9π(11-6√(2)) cm²

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3026716

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Sir Mike Ambrose is the author of the question. Let the radius of the ascribed semicircle be 2 units. Therefore; Radius of the inscribed circle is 1 unit. It implies; Area R is; Area sector with radius 2 units and angle 45° - Area triangle with height and base √(2) unit each. = (45*2*2π÷360)-(½(√(2))² = ½(π)-1 = ½(π-2) square unit. Area S is; Area triangle with height and base √(2) unit each - Area sector with radius 1 unit and angle 90° + Area triangle with hei...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3024978

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Let a be the side of the square. cos30 = b/8 b = 4√(3) cm. sin30 = c/8 c = 4 cm. a = b+12 a = (12+4√(3)) cm. Area Square is; a² = (12+4√(3))² = 358.27687752661 cm²  d² = 12²+4²-2*4*12cos30 d = 8.76707255797 cm. (8.76707255797/sin30) = (12/sine) e = 180-43.18678543201 e = 136.81321456799° f = 360-e-180 f = 43.18678543201° g² = 8²+8.76707255797²+2*8*8.76707255797cos43.18678543201 g = 6.21165708246 cm. (6.21165708246/sin43.18678543201) = (8.76707255797/sinh)...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3023335

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Let the single side length of the two congruent inscribed regular pentagon be 1 unit. Area Green is; 0.5*5(1/(2tan(180/5))) = 1.72047740059 square units. Calculating Area Shaded. a = ⅕(180*3) = 108° Where a is the single interior angle of the congruent inscribed regular pentagon. b² = 2-2cos108 b = 1.61803398875 units. c = 1+b c = 2.61803398875 units. d² = 2.61803398875²+1²-2*1*2.61803398875cos72 d = 2.49721204096 units. Where d is the radius of the inscribed...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3021112

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Sir Mike Ambrose is the author of the question. Area Orange exactly in square cm decimal is; Area triangle with height 1.64419338427 cm and base (4.95325421888sin129.5411167921) cm = ½*1.64419338427*(4.95325421888sin129.5411167921) = 3.14023734337 cm²

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3019244

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a = atan(3/2)° b = atan(2/3)° b = Angle BEG. tan(atan(2/3)) = c/2 ⅔ = c/2 c = (4/3) cm. c = BG. OG = 2-(4/3) OG = ⅔ cm. Notice; Radius of the circle is 2 cm. Angle OGH = 180-atan(3/2) = 123.69006752598° (2/sin123.69006752598) = ((⅔)/sind) d = 16.10211375199° d = Angle OHG. Angle GOH = 180-16.1021137519-123.69006752598 = 40.20781872212° It implies; Length GH is; (GH/sin40.20781872212) = ((2/3)/sin16.10211375199) GH = 1.55173771485 cm.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3017238

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Sir Mike Ambrose is the author of the question  Let the side of the regular Pentagon be 2 units. Therefore; Area orange is; Area triangle with height 1.7013016167 units and base 1.8345763534sin(18) units = ½*1.7013016167*1.8345763534sin(18) = 0.48224693327 square units. Area blue is; Area trapezoid with parallel sides 0.21654236465 units and 1 unit, and height 1.9021130326 units. ½*1.9021130326(0.21654236465+1) = 1.15700054326 square units. It implies; Area Orang...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3015837

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a² = 2*12²-2*12²cos120 a = 12√(3) cm. a = 20.78460969083 cm. a = AB. b = 2a b = 24√(3) cm. b = 41.56921938165 cm. b = AC. c² = 12²+41.56921938165²-24*41.56921938165cos30 c = 31.74901573277 cm. c = CO1 (31.74901573277/sin30) = (12/sind) d = 10.89339464913° d = Angle O1CA. e = 180-10.89339464913-30 e = 139.10660535087° e = Angle AO1C. f = asin(12/31.74901573277)  f = 22.2076542986° f = Angle O1CD. cos22.2076542986 = g/31.74901573277 g = 29.39387691339 cm. g = C...
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