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Four principles of deeply effective math teaching

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Principle 1: Let It Make Sense Let us strive to teach for understanding of mathematical concepts and procedures, the "why" something works, and not only the "how". This understanding, as I'm sure you realize, doesn't always come immediately. It may take even several years to grasp a concept. For example, place value is something children understand partially at first, and then that deepens over a few years. This is why many math curricula use spiraling: they come back to a concept the next yea...

Mathematics Question and Solution

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The side length of the congruent Hexagons is 2 unit. Area hexagon is; (6*2²)/(4tan30) = 6√(3)) square units. a² = 8-8cos30 a = √(8-4√(3)) unit. Area ABC is; ½(√(8-4√(3)))²sin60 = (2√(3)-3) square units. (d) Area Hexagon ÷ Area ABC exactly is; (6√(3)) ÷ (2√(3)-3) = 6(2+√(3)) (c) Calculating Area Green to 2 decimal places. b = a + √(2²+2²) b = √(8-4√(3))+2√(2) b = (√(2)+√(6)) units. b = 3.86370330516 units.  c² = 8-8cos120 c = 2√(3) units. Area Green is; 2((0.5x2*2sin120) + (0.5*2√(3)*(√(2)+√(6)...

Mathematics Question and Solution

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Let the biggest regular pentagon side length be 2 units. sin72 = a/2 a = 1.90211303259 units. tan72 = (1.90211303259/b) b = 0.61803398875 unit. c = 2b c = 1.2360679775 units. Where c is the side length of the regular red and blue pentagon. Calculating area of the regular red and blue pentagon. (5*1.2360679775²)/(4tan36) = 2.6286555606 square units. d² = 8-8cos108 d = 3.2360679775 units. e = ½(3.2360679775-c) e = 1 unit. f² = 8-8cos36 f = 1.2360679775 units. g² = 2-2cos36 g = 0.61803398875 unit...

Mathematics Question and Solution

https://onlineedumath.websites.co.in/update/mathematics-question-and-solution/1769331

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a = atan(⅓)° ⅓ = b/3 b = 1 unit. It implies; Area Red is; Area triangle with height 1 unit and base 3 units + ½(2(area quarter circle with radius 3 units - area triangle with height and base 3 units respectively))) = ½(1*3) + ½(2(¼(π*3²) - ½(3*3))) = ½(3) + ¼(9)π - ½(9) = ¼(9π) - ½(6) = ¼(9π-12) square units. = ¾(3π-4) square units.

Mathematics Question and Solution

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Let DE be 1 unit. AC = 4 units. Area ABC is; 8sin60 = 4√(3) square units. a² = 1+2²-4cos45 a = 1.47362575821 units. (1.47362575821/sin45) = (1/sinb) b = 28.6750500631° c = 60-b c = 31.3249499369° d = 360--60-150  d = 150° e = 240-d e = 90° f² = 1²+1² f = √(2) units. g = 180-15-45-60 g = 60° h² = 4²+1.47362575821²-8*1.47362575821cos31.3249499369 h = 2.84622917461 units. (2.84622917461/sin31.3249499369) = (1.47362575821/sini) i = 15.61499741821° j = 60-i j = 44.38500258179° k = 120...

Mathematics Question and Solution

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Let the side of the regular octagon be a. Calculating a. a² = 8 a = √(8) a = 2√(2) units. 2b² = (2√(2))² b = 2 units. c = 2√(2)+2+2 c = (2√(2)+4) units. Where c is the length of the inscribed rectangle. d = c-2(2√(2)) d = (2√(2)+4)-4√(2) d = (4-2√(2)) units. Where d is the width of the inscribed rectangle. Area Rectangle is; cd = (2√(2)+4)*(4-2√(2)) = 8 square units.

Mathematics Question and Solution

https://onlineedumath.websites.co.in/update/mathematics-question-and-solution/1768938

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Let the square side be 2 units. tan30 = a/2 a = ⅓(2√(3)) unit. sin60 = 2/b b = ⅓(4√(3)) units. c = 2-a c = ⅓(6-2√(3)) units. It implies; Area Shaded is; 2(½*(⅓(6-2√(3)))²sin60) + 2*⅓(6-2√(3)) = ⅓(4√(3)) square units. Area of the composite shape is; Area Shaded + 2(½*(⅓(4√(3)))²sin60) = ⅓(4√(3)) + ⅓(8√(3)) = 4√(3) square units. Therefore; Fraction Shaded is; ⅓(4√(3)) ÷ 4√(3) = ⅓

How to Become Brilliant in Maths: Tips And Tricks To Improve Mathematics by Akshi Dusad

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1. Do All Homework A student must not treat homework as a choice. It is the most important and effective way that students should practice to master the concepts taught in the classroom. Students should set up a place and time that can motivate them to complete the homework. 2. Try Not to Miss Class Math class moves fast and a new concept starts every day. What students learn today builds their tomorrow. Missing a math class can create issues for students while studying further concepts....

Short Story for Kids written by: Valeria Sofia Carrero Vargas.

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Once upon a time there was a child who really loved studying, but one day, his teacher scolded him because he had been late to school. The next day, Charlie was late again, and the teacher advised him that could not happen again, and that she was going to talk with his parents. Charlie stayed quiet. The next morning, the kid arrived on time to school, but the teacher told him that his homework were bad, that he had to pay attention in class when she was explaining and encouraged him to ask her...

We are smart and clever!

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He is Ogheneruemu, a grade 4 pupil and a proud Online Edumath learner. He scored 96% in his end of term 2 Mathematics total Assessment, we are super proud of Him. Ogheneruemu is smart and clever
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