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Short Video of Our Teaching and Learning Activities

https://onlineedumath.com/update/short-video-of-our-teaching-and-learning-activitie/2160952

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Please, browse through the link below to review short video of our teaching and learning activities. Thank you.  Video 103. Class with Derick and Zino (year 7 and year 6 respectively) 03/10/2023 https://www.facebook.com/100085657676431/posts/pfbid0s2Q2ihgbv8C4nrU1T4DivkEJmVAaA8D4ytyWNDNTzypuTnaFdMTrmB4be23iRQ2Jl/?app=fbl

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2160284

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Sir Mike Ambrose is the author of the question. Calculating k. 3k² = 108 k = 6 units. The equation of the curve is; y = 4x-⅓(x²) Area R is; Area under the curve at x=0 and x=(6-3√(2)). = 2(6-3√(2))²-(6-3√(2))²/9 = 6(8-5√(2)) square units. Area S is; Area rectangle with length 12 units and width 6 units - Area trapezoid with parallel sides 12 units and 9 units, and height 3 units - Area under the curve at x=3 and x=6. = (12*6) - ½*3(12+9) - 33 = 72 - ½(63) - 33 = 39 - ½(63) = ½(15) square un...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2158490

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Sir Mike Ambrose is the author of the question. Let the side of the regular quadrilateral (square) be 4 units. Area square is; 4² = 16 square units. Area Red is; Area triangle with height 4.56295238924 units and base 3.14062240575sin46.50530982298 - Area triangle with height 1.46815433032 units and base 3.14062240575sin46.50530982298 = 5.19860210712 - 1.6724847454  = 3.52611736172 square units. It implies; Area Red ÷ Area Square to 2 decimal places is; 3.52611736172 ÷ 16 = 0.22038233511 ...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2156623

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tana = 4/8 a = atan(½)° b = (180-2atan(½))° It implies; Area Orange is; Area triangle with base 8 units and height 4 units - Area square with side 4 units + Area quarter circle with radius 4 units - Area sector with radius 4 units and angle (180-2atan(½))° + Area triangle with base 4 units and height 4sin(180-2atan(½)) units. = ½(8*4)-(4*4)+¼(4*4π)-((180-2atan(½))*4*4π/360)+½(4*4sin(180-2atan(½))) = 16-16+12.5663706144-17.7143794847+6.4 = 12.5663706144-17.7143794847+6.4 = 1.2519911297 squa...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2154713

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Sir Mike Ambrose is the author of the question. Let the side of the square be 2 units. Therefore; Area square is; 2² = 4 square units. Radius of the inscribed circle, r is; sin52.5 = r/1.04420953776 r = 0.82842712475 unit. Shaded Area is; 2(area triangle with height 0.63567449039 units and base 0.82842712475 units) - Area sector with radius 0.82842712475 and angle 75°. = 2(½*0.63567449039*0.82842712475) - (75π*0.82842712475²÷360) = 0.52660999035 - 0.44917673705  = 0.0774332533 square units....

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2153152

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Sir Mike Ambrose is the author of the question. Let the side of the regular hexagon be 2 units. Therefore; Area Green is; Area regular equilateral triangle with side √(3) units. ½*√(3)*√(3)sin60 = ¼(3√(3)) square units. Area Blue is; Area trapezoid with parallel sides √(3) units and 2√(3) units, and height ½ unit - Area triangle with height ⅓√(3) units. ½*½(√(3)+2√(3)) - ½*1*⅓√(3) = ¼(3√(3))-√(3)/6 = 7√(3)/12 square units. Area Orange is; Area trapezoid with parallel sides 1 unit and ½ uni...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2149344

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Sir Mike Ambrose is the author of the question. Let the side of the regular octagon be 1 unit. (a) Calculating alpha exactly. Let it be x. x = atan(1/(√(2)+1) x = 22.5° (b) Calculating Area Yellow ÷ Area Green exactly. Area yellow is; Area triangle with height √(2) units and base (2-√(2)) unit. = ½*√(2)*(2-√(2)) = (√(2)-1) square units. Area green is; Area trapezoid with parallel sides 1 unit and √(2) units, and height ½√(2) unit. = ½*½√(2)(√(2)+1) = ¼(2+√(2)) square units. It implies; A...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2147406

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Sir Mike Ambrose is the author of the question. Let the side of the regular hexagon be 2 units. Area Regular hexagon is; ½(12)*(2/(2tan(180/6))) = 6/tan30 = 6√(3) square units. Area Shaded is; Area triangle with height and base 2 units respectively - Are triangle with height (2-√(3)) unit and base 0.28144275258sin45 - Area sector with radius 1 unit and angle 120° + Area triangle with height 1 unit and base sin120 units.   ½(2*2) - ½(2-√(3))*0.28144275258sin45 - (120π÷360) + ½(sin120) = 2...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2147400

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Sir Mike Ambrose is the author of the question. Let the side of the inscribed regular pentagon be 2 units. Therefore; Length Red (AD) is; 2+2(2cos72) = 2+4cos72 = 3.2360679775 units. Calculating Length Blue. Let the radius of the inscribed circle be r. r is; tan27 = r/(3.2360679775-2sin72-r) tan27=r/(1.33395494491-r) 0.67968399291=1.50952544949r r = 0.45026335471 unit.  Length Blue is;  1.1163084098tan54 + r  1.1163084098tan54+0.45026335471 = 1.98673006763 units....

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2145374

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Notice; Quadrilateral KMHE and Quadrilateral HMLF are similar plane shapes. Therefore; Let MH be x. Calculate x. x = 4 9 = x, Cross Multiply. It implies; x² = 9*4 x² = 36 x = 6 cm. Therefore; MH = 6 cm.
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