Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2520241

Let the radius of the inscribed circle be a. tanb = 4/3 b = atan(4/3)° c = ½(b) c = ½(atan(4/3))° d = (3-a) units. It implies; tan(½(atan(4/3))) = a/(3-a) ½ = a/(3-a) 2a = 3-a a = 1 unit. Again, a is the radius of the inscribed circle. e = 4-1 e = 3 units. f = √(4²+3²)-(3-1) f = 5-2 f = 3 units. tang = 3/4 g = atan(3/4)° h = ½(180-g) h = ½(180-atan(3/4)) h = 71.5650511771° tanj = 3/3 j = atan(1) j = 45° It implies, the required angle, x is; x =...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2520234

Let the inscribed square side length be a. 2² = 1²+b² b² = 4-1 b = √(3) units. c = 2b+a c = (a+2√(3)) units. c is BC. d = (a+1) units. sin60 = (a+1)/e ½√(3) = (a+1)/e √(3)e = 2a+2 e = ⅓(2√(3)a+2√(3)) units. e is CQ. f = a+e f = (a+⅓(2√(3)a+2√(3))) units. f is AC. Therefore, calculating a, side length of the square. Equating c and f. (a+2√(3)) = (a+⅓(2√(3)a+2√(3))) 2√(3) = ⅓(2√(3)a+2√(3)) 6√(3) = 2√(3)a+2√(3) 2√(3)a = 6√(3)-2√(3) 2√(3)a = 4√(3) a = 2 uni...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2520208

Let x be 1 unit. a - 1 1 - √(2) Cross Multiply. √(2)a = 1 a = ½√(2) units. It implies; Area yellow is; ½*1*½√(2) = ¼√(2) square units. Area Blue is; ½(√(2)+½√(2))*1 = ½(½(3√(2))) = ¼(3√(2)) square units. Therefore; Blue Area ÷ Yellow Area is; ¼(3√(2))÷¼√(2) = 3

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2515413

Let the side length of the two congruent inscribed regular hexagon be 1 unit each. Calculating the radius, a, of one of the two congruent inscribed yellow circles. tan60 = a/(0.5) a = 0.8660254038 units. a = ½√(3) units. Therefore, area inscribed yellow circles is; 2πr² = 2*π*(½√(3))² = 2*π*¼*3 = ½(3π) square units. Calculating the radius of the ascribed semi circle. b² = 2-2cos120 b = √(3) units. c = 2b c = 2√(3) units. d² = c²+0.5² Where d is the radius of th...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2515207

a = 180-60 a = 120° b² = 4²+6²-2*4*6cos120 b = 2√(19) units. b = 8.7177978871 units. b is the side length of the inscribed regular triangle ABC (equilateral triangle). (8.7177978871/sin120) = (4/sinc) c = 23.4132244464° d = 60+c d = 83.4132244464° Therefore, length BD is; (BD)² = 6²+8.7177978871²-2*6*8.7177978871cos83.4132244464 BD = 10 units.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2515184

a² = 3²+4² a = √(25) a = 5 units. 3b+4b+5b = 3*4 12b = 12 b = 1 unit. b is the radius of the inscribed circle. tanc = 3/4 c = atan(¾)° d = ½(180-atan(¾)) d = 71.5650511771° tane = 4/3 e = atan(4/3)° f = ½(180-atan(4/3)) f = 63.4349488229° sin71.5650511771 = 1/g g = 1.0540925534 units. sin63.4349488229 = 1/h h = 1.1180339888 units. j = 90-71.5650511771 j = 18.4349488229° k = 90-63.4349488229 k = 26.5650511771° l = 180-26.5650511771-18.4349488229 l =...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2514912

Let the bigger square side length be 1 unit. a² = 2(1)² a = √(2) units. a is the diagonal of a bigger square. Let b be the side length of the big square. c = (1+b) units. It implies; Calculating b. √(2)² = (1+b)²+b² 2 = 1+2b+b²+b² 2b²+2b-1 = 0 Resolving the quadratic equation via completing the square approach to get b, side length of the big square. 2b²+2b-1 = 0 b²+b = ½ (b+½)² = ½+(½)² (b+½)² = ¼(3) b = -½±½√(3) It implies; b = ½√(3)-½ b = ½(√(3)-1) units...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2513313

Let the side length of the regular pentagon be 1 unit. a² = 1+0.5²-2*0.5cos108 a = 1.2486060205 units. (1.2486060205/sin108) = (0.5/sinb) b = 22.3861775592° c = 180-108-b c = 49.6138224408° d = c-b d = 49.6138224408-22.3861775592 d = 27.2276448816° e = 180-2c e = 180-2*49.6138224408 e = 80.7723551184° f = 180-27.2276448816-e f = 72° (1.2486060205/sin72) = (g/sin27.2276448816) g = 0.6006698572 units. h² = 0.6006698572²+0.5²-2*0.6006698572*0.5cos49.6138224408...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2513053

tana = 10/5 a = atan(2)° b = 180-2a b = (180-2atan(2))° c² = 5²+5²-2*5*5cos(180-2atan(2)) c = 4.472135955 units. d = ½(90-(180-2atan(2))) d = atan(2)° e = 90-d e = 26.5650511771° Shaded Area is; ½*4.472135955*10sin26.5650511771 = 22.146600355 square units.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2513010

Let the side length of the regular pentagon be 1 unit. a = 108-90 a = 18° 108° is the single interior angle of the regular pentagon. b = 90-18 b = 72° c =108-72 c = 36° sin18 = d/1 d = 0.3090169944 units. e² = 1+0.3090169944²-2*0.3090169944cos36 e = 0.7716809592 units. (0.7716809592/sin36) = (0.3090169944/sinf) f = 13.6138224422° g² = 1²+0.5²-2*0.5cos108 g = 1.2486060205 units. (1.2486060205/sin108) = (0.5/sinh) h = 22.3861775592° j = 108-13.6138224422-h...

You Searched for "delta state office ekrejeta house 2 zenith bank abraka delta state nigeria"

2293 result found.

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

OnlineEdumath

Socials

Facebook Page

Quick Links

Reach Us

Safety and Abuse Reporting

Thanks for being awesome!

Are you sure you want to report abuse against this website?

Search

You Searched for "delta state office ekrejeta house 2 zenith bank abraka delta state nigeria"

2293 result found.

Subscribe to our mailing list for latest updates.

Safety and Abuse Reporting

Thanks for being awesome!

Are you sure you want to report abuse against this website?