Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3168936

Calculating red Area. Notice. 3x = 4-x 4x = 4 x = 1 unit. Where x is the radius of the red quarter circle and the inscribed white half circle. y = 4-x And x = 1 units. y = 4-1 y = 3 units. y is the radius of the bigger quarter circle. Area red is; ¼(πy²)-¼(πx²) = ¼*π(3²-1²) = ¼*π(9-1) = ¼*π*8 = 2π square units.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3161756

Green Area is; Area square with length 4 units - Area quarter circle with radius 2 units - Area square with length 2 units - 3(Area square with length 1 unit) - Area square with length 3 units + Area quarter circle with radius 3 units - Area square with length 2 units + Area quarter circle with radius 2 units - Area quarter circle with radius 1 unit. = 16 - ¼(4π) - 4 - 3 - 9 + ¼(9π) - 4 + ¼(4π) - ¼(π) = 16 - 20 + ¼(9π - π) = ¼(8π) - 4 = 2π - 4 = 2(π-2) square units.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3157726

Let a be the radius of the quarter circle. b = (a-6) units. c = (a-8) units. Let x be the side length of the square. x² = (a-8)²+(a-6)² x² = a²-16a+64+a²-12a+36 x² = 2a²-28a+100 x = √(2a²-28a+100) units. d = ½(45) d = 22.5° It implies; √(2a²-28a+100)² = a²+(a-8)²-2*a(a-8)cos22.5 2a²-28a+100 = 2a²-16a+64-2a²cos22.5+16acos22.5 36-12a = 14.7820725202a-1.84775906502a² 1.84775906502a²-26.7820725202a+36 = 0 Therefore; a = 13 units. Again, a is the radius of...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3155027

Kindly move the question left/right one time to review the analysis of the question (plane shape). Thank you nicely. Calculating R, radius of the quarter circle. a = 3+4 a = 7 units. b² = 2(4)² b = 4√(2) units. c = R-b c = (R-4√(2)) units. d = 180-45 d = 135° R is; Observing cosine rule. R² = 7²+(R-4√(2))²-2*7(R-4√(2))cos135 R² = 49+R²-8√(2)R+32+7√(2)(R-4√(2)) 8√(2)R = 81+7√(2)R-56 √(2)R = 25 R = ½(25√(2)) units. R = 17.6776695297 units. Or e² = 3²+4² e...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3151650

Let the radius of the quarter circle be 1 unit. 2a² = 1 a² = ½ a = ½√(2) units. a is the side length of the inscribed square. b = 1-a b = 1-½√(2) b = ½(2-√(2)) units. b is the side length of the green square G. Area green square is; b² = (½(2-√(2)))² = ½(3-2√(2)) square units. Calculating Area R, Red Area. (½√(2)+c)²+c² = 1² ½+√(2)c+2c² = 1 4c²+2√(2)c-1 = 0 (c+¼√(2))² = ¼ (c+¼√(2))² = ¼+(¼√(2))² c = -¼√(2)±√(6/16) c = -¼√(2)±¼√(6) Therefore; c ≠ -¼√(2)-¼√(6) c = -¼√(2)+¼√(6) c = ¼(√(6...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3146954

Let the radius of the quarter circle be 1 unit. b = (a+1) units. a is AD = DE. a² = 2-2cosx 2cosx = 2-a² cosx = ½(2-a²) --- (1). cosx = 1/(1+a) --- (2). Calculating a. Equating (1) and (2). ½(2-a²) = 1/(1+a) 2 = (2-a²)(1+a) 2 = 2+2a-a²-a³ 0 = 2a-a²-a³ a²+a-2 = 0 (a+½)² = 2+(+½)² (a+½)² = ¼(9) a = -½±√(9/4) a = -½±(3/2) Therefore; a ≠ -½-(3/2) a = -½+(3/2) a = 1 unit. Recall. cosx = 1/(1+a) at (1). And a = 1 unit. cosx = 1/(1+1) cosx = ½ x = 60° It...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3137623

Calculating R, radius of the quarter circle. a = 3+4 a = 7 units. b² = 2(4)² b = 4√(2) units. c = R-b c = (R-4√(2)) units. d = 180-45 d = 135° R is; R² = 7²+(R-4√(2))²-2*7(R-4√(2))cos135 R² = 49+R²-8√(2)R+32+7√(2)(R-4√(2)) 8√(2)R = 81+7√(2)R-56 √(2)R = 25 R = ½(25√(2)) units. R = 17.6776695297 units.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3136722

Let angle AOB be a. Let b = AD = OB = OD. b is the radius of the quarter circle. Calculating b. 2² = 2b²-2b²cosa 2b²cosa = 2b²-4 b²cosa = b²-2 cosa = (b²-2)/b² --- (1). 4² = b²+(2b)²-4b²cosa 16 = 5b²-4b²cosa 4b²cosa = 5b²-16 cosa = (5b²-16)/(4b²) --- (2). Equating (1) and (2). (b²-2)/b² = (5b²-16)/(4b²) 4(b²-2) = 5b²-16 4b²-8 = 5b²-16 b² = 8 b = √(8) b = 2√(2) units. Again, b is the radius of the quarter circle.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3135856

a = 4+4 a = 8 units. a is the radius of the quarter circle. cosb = ⅛(0.5*4) b = acos(¼)° cosb = c/8 c = 8cos(acos(¼)) c = ¼(8) c = 2 units. c is the width of the inscribed rectangle. sinb = d/8 d = 8sin(acos(¼)) d = 7.74596669241 units. Therefore, area inscribed rectangle is; cd = 2*7.74596669241 = 15.4919333848 square units.r

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3134184

Area blue is; 2(area quarter circle with radius 8 cm - area isosceles right-angled triangle with equal lengths 8 cm) + 2(area quarter circle with radius 4 cm - area isosceles right-angled triangle with equal lengths 4 cm) = 2((¼*8*8π)-(½*8*8))+2((¼*4*4π)-½*4*4)) = 2(16π-32)+2(4π-8) = 2(16π-32+4π-8) = 2(20π-40) = 40(π-2) cm²

You Searched for "nft art"

393 result found.

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

OnlineEdumath

Socials

Facebook Page

Quick Links

Reach Us

Safety and Abuse Reporting

Thanks for being awesome!

Are you sure you want to report abuse against this website?

Search

You Searched for "nft art"

393 result found.

Subscribe to our mailing list for latest updates.

Safety and Abuse Reporting

Thanks for being awesome!

Are you sure you want to report abuse against this website?