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Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3457816

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Sir Mike Ambrose is the author of the question.Side length of the square is;Let it be x.x = √((16*34)-144)x = √(400)x = 20 cm.Therefore;Area Orange exactly in decimal cm² is;Half area square with side 20 cm - Area triangle with height 7.88405797101 cm and base ⅓(32sin(2atan(3/5))) cm - Area triangle with height 8.74642784227 cm and base (12sin(atan(5/3))) cm= ½(20²) - ½(7.88405797101*⅓(32sin(2atan(3/5)))) - ½(8.74642784227*(12sin(atan(5/3))))= 200 - 37.1014492753 - 45= 155 - 37.1014492753= 117....

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3438244

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Sir Mike Ambrose is the author of the question.Area blue exactly is square units decimal form is;½(Area triangle with height (2√(2)+2√(2+√(3))) units and base 12.9282032303sin75 units - Area triangle with height 2 units and base (2sin150) units - Area trapezoid with two parallel side (2√(2)+2√(2+√(3))) units and (2√(2+√(3))) units, and height √(2) units)=½((0.5*(2√(2)+2√(2+√(3)))*12.9282032303sin75) - (0.5*2*2sin150) - (0.5*√(2)((2√(2)+2√(2+√(3)))+(2√(2+√(3)))))= ½(41.7846096909 - 1 - 7.4641016...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3424247

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Sir Mike Ambrose is the author of the question.a² = 10²+16²-2*10*16cos120a = 2√(129) units.Where a is length AC.(3√(129)/sin120) = (16/sinb)b = 37.58908946897°c = 90-bc = 52.41091053103° d = 60-bd = 22.41091053103°e = 90-de = 67.58908946897° f = 90-60f = 30°cos37.58908946897 = g/10g = 7.92405815693 units.i = 30+37.58908946897i = 67.58908946897°tan67.58908946897 = j/7.92405815693j = 19.2148198619 units.Where j is the radius of the arc.sin67.58908946897 = 19.2148198619/kk = 20.78460969082 units.l...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3423223

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Sir Mike Ambrose is the author of the question.The side of area green, inscribed square is;Let it be x.Therefore;1.11496246101x + 0.82101781219x = 27.36726040631.9359802732x = 27.3672604063x = 14.1361256544 cmTherefore;Exact perimeter of green area in decimal cm is;4(14.1361256544)= 56.5445026176 cm

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3354036

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Sir Mike Ambrose is the author of the question. Calculating Area Green Total. Area green total exactly in decimal cm² is; Area triangle with two side (12-6√(3)) cm each and angle 60° + Area triangle with side 3.46410161514 cm and 2.5358983849 cm, and angle 60° + Area triangle with side 6 cm and 3.10582854123 cm, and angle 45° = 1.11920087684 + 3.80384757735 + 6.58845726812 = 11.5115057223 cm²

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3341152

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Area Orangle ÷ Area Large Square to 3 d. p. Let the side length of the large square be x. Calculating x. 25=x²+64-(16xcos20) Therefore; x = 11.70244 cm It implies; Area large square is; 11.70244² = 136.947101954 cm² Area orange is; Area triangle with height and base 8 cm each - Area triangle with two side 2.91176187413 cm and 2.27177411013 cm, and angle 70° = ½(8)² - ½(2.91176187413*2.27177411013)sin70 = 32 - 3.107970027 = 28.892029973 cm² Therefore; Area Orangle ÷ Area Large S...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3294509

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Calculating R, radius of the inscribed circle. cosa = BA/BC a = acos(4/8) a = 60° a is angle ABC. b = ½(a) b = 30° b is angle ABD = angle CBD. sin30 = c/8 c = 4 cm. c is CD. cos30 = d/8 d = 4√(3) cm. d is BD. Calculating R. 4R+8R+4√(3)R = 4*4√(3) (12+4√(3))R = 16√(3) (3+√(3))R = 4√(3) R = (4√(3))/(3+√(3)) R = 2√(3)-2 R = 2(√(3)-1) units. R = 1.46410161514 units.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3249575

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Sir Mike Ambrose is the author of the question. Calculating Area yellow ÷ Area green. Let the side length of the regular hexagon be 1 unit. Therefore; Area green is; Area triangle with height 1 unit and base ⅓√(3) units. = ½(⅓√(3)*1) = √(3)/6 square units. Area yellow is; Area triangle with two length 0.40929915222 units and 1 units, and angle (90-atan(⅓(2√(3))))° = ½(0.40929915222*1)sin(90-atan(⅓(2√(3)))) = 0.13397459621 square units. It implies; Area yel...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3221444

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Calculating shaded yellow area. Let x be the side length of the ascribed regular decagon. Let y be the side length of the two equal inscribed regular pentagons. a = ⅒*180(10-2) a = 144° a is the single interior angle of the ascribed regular decagon. b = ⅕*180(5-2) b = 108° b is the single interior angle of the both equal inscribed regular pentagons. c = (1+y) units. It implies; (1+y)² = 2x²-2x²cos144 y = 1.90211303259x-1 --- (1). d² = 2y²-2y²cos108 d = 1.61803398...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3219513

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Sir Mike Ambrose is the author of the question. Calculating Exactly Green Area. Let x be the side length of each of the three inscribed congruent squares. a² = 2x² a = √(2)x a is the diagonal of the squares. b = 45-30 b = 15° cos15 = c/(√(2)x) c = ½(√(3)+1)x units. c = 1.36602540378x units. d = c+x d = ½(1+√(3))x+x d = ½(3+√(3))x units. d is the height of the ascribed regular hexagon. e² = 2²+2²-2*2*2cos120 e = √(8+4) e = 2√(3) units. e = d. Calculating x....

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Short Videos of Our Teaching and Learning Activities

https://onlineedumath.com/pages/short-videos-of-our-teaching-and-learning-activities/273743

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Please, highlight and open/browse the links below to view videos of our teaching and learning activities. Thank you. Video 1. Class with Adesuwa (year 5) 27/06/2023 https://www.facebook.com/100003984568865/posts/pfbid02VGXZkxZYksDaBSZXhbkir8GKETEiU2fCQobAVZE4Yv84HRaQ3NL1XvAMTRTxsNs3l/?app=fbl Video 2. Class with Zino and Ruemu (year 4) 27/06/2023 https://www.facebook.com/100003984568865/posts/pfbid038EyeWYY8Du4XgbEb7mbz33DS7XAvYWjXTwrE6HRfC4qpFTqCX6YVFYmnCeDBfEWHl/?app=fbl Video 3. Class with A...
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